To expand $(8x - 5y)(8x - 5y)$, we can apply the formula for squaring a binomial, which is:

$(a - b)^2 = a^2 - 2ab + b^2$

Here, $a = 8x$ and $b = 5y$. Using the formula:

$(8x - 5y)^2 = (8x)^2 - 2(8x)(5y) + (5y)^2$

Now calculate each term:

• $(8x)^2 = 64x^2$
• $-2(8x)(5y) = -80xy$
• $(5y)^2 = 25y^2$

So the expanded form is:

$64x^2 - 80xy + 25y^2$

Would you like further details on any part of this expansion?

Here are 5 related questions for practice:

1. What is the expanded form of $(7x - 2y)^2$?
2. How would you expand $(3x + 4y)(3x + 4y)$?
3. What is the result of expanding $(9x + 6y)^2$?
4. How does the expansion change if both terms are positive, e.g., $(5x + 7y)(5x + 7y)$?
5. Can you use the distributive property to expand $(6x - y)(6x + y)$?

Tip: When expanding binomials, remember to carefully apply the distributive property to avoid sign errors.