To expand $(4x - 3y)^2$, we can use the formula for squaring a binomial:

$(a - b)^2 = a^2 - 2ab + b^2$

In this case:

• $a = 4x$
• $b = 3y$

Now, apply the formula:

$(4x - 3y)^2 = (4x)^2 - 2(4x)(3y) + (3y)^2$

First, calculate each term:

• $(4x)^2 = 16x^2$
• $2(4x)(3y) = 24xy$
• $(3y)^2 = 9y^2$

Putting it all together:

$(4x - 3y)^2 = 16x^2 - 24xy + 9y^2$

So, the expanded form is:

$16x^2 - 24xy + 9y^2$

Would you like more details or have any questions?

Here are 5 related questions to explore:

1. What happens when you expand $(4x + 3y)^2$?
2. Can you apply the same method to $(5x - 2y)^2$?
3. How do you factor $16x^2 - 24xy + 9y^2$ back to the original form?
4. What is the general formula for expanding $(ax - by)^2$?
5. How does the expansion change if the expression is $(4x - 3y)^3$?

Tip: When squaring binomials, always double-check each intermediate term to avoid sign errors!