Math Problem Statement

Use the frequency distribution shown below to construct an expanded frequency distribution. High Temperatures ​(degrees Upper F​) Class 17​-27 28​-38 39​-49 50​-60 61​-71 72​-82 83​-93

​Frequency, f 18 42 68 69 78 68 22 Question content area bottom Part 1 Complete the table below. High Temperatures ​(degrees Upper F​)     ​(Round to the nearest hundredth as​ needed.) Class ​Frequency, f Midpoint Relative frequency Cumulative frequency 17​-27 18    enter your response here    enter your response here    enter your response here

Solution

We are tasked with constructing an expanded frequency distribution for the given frequency data, which includes calculating midpoints, relative frequencies, and cumulative frequencies.

Let’s break it down step by step.

1. Midpoint Calculation:

The midpoint for each class is the average of the lower and upper boundaries. The formula for the midpoint is:

Midpoint=Lower boundary+Upper boundary2\text{Midpoint} = \frac{\text{Lower boundary} + \text{Upper boundary}}{2}

2. Relative Frequency Calculation:

The relative frequency is the fraction or percentage of the total frequency for each class. The formula is:

Relative Frequency=Frequency of the classTotal Frequency\text{Relative Frequency} = \frac{\text{Frequency of the class}}{\text{Total Frequency}}

3. Cumulative Frequency Calculation:

Cumulative frequency is the running total of the frequencies up to the current class.

Now, let's apply this to each class:

Step 1: Midpoints

For each class, we calculate the midpoint:

  1. 172717 - 27: 17+272=22\frac{17 + 27}{2} = 22
  2. 283828 - 38: 28+382=33\frac{28 + 38}{2} = 33
  3. 394939 - 49: 39+492=44\frac{39 + 49}{2} = 44
  4. 506050 - 60: 50+602=55\frac{50 + 60}{2} = 55
  5. 617161 - 71: 61+712=66\frac{61 + 71}{2} = 66
  6. 728272 - 82: 72+822=77\frac{72 + 82}{2} = 77
  7. 839383 - 93: 83+932=88\frac{83 + 93}{2} = 88

Step 2: Relative Frequencies

First, sum the total frequencies:

18+42+68+69+78+68+22=36518 + 42 + 68 + 69 + 78 + 68 + 22 = 365

Now calculate the relative frequency for each class:

  1. 183650.0493\frac{18}{365} \approx 0.0493
  2. 423650.1151\frac{42}{365} \approx 0.1151
  3. 683650.1863\frac{68}{365} \approx 0.1863
  4. 693650.1890\frac{69}{365} \approx 0.1890
  5. 783650.2137\frac{78}{365} \approx 0.2137
  6. 683650.1863\frac{68}{365} \approx 0.1863
  7. 223650.0603\frac{22}{365} \approx 0.0603

Step 3: Cumulative Frequencies

Cumulative frequencies are calculated by adding the frequency of the current class to the sum of the frequencies of the previous classes:

  1. 1818
  2. 18+42=6018 + 42 = 60
  3. 60+68=12860 + 68 = 128
  4. 128+69=197128 + 69 = 197
  5. 197+78=275197 + 78 = 275
  6. 275+68=343275 + 68 = 343
  7. 343+22=365343 + 22 = 365

Now we can fill in the table:

High Temperatures (°F)Frequency (f)MidpointRelative FrequencyCumulative Frequency
17-2718220.049318
28-3842330.115160
39-4968440.1863128
50-60

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Statistics
Frequency Distribution
Midpoint
Relative Frequency
Cumulative Frequency

Formulas

Midpoint = (Lower boundary + Upper boundary) / 2
Relative Frequency = Frequency of the class / Total Frequency
Cumulative Frequency = Running total of the frequencies

Theorems

None

Suitable Grade Level

Grades 9-12