The problem asks to expand $(x - 4)^3$ and identify the coefficients of the terms in the expanded form.

We can use the binomial expansion formula to expand $(x - 4)^3$:

$(a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3$

In this case, $a = x$ and $b = 4$, so:

$(x - 4)^3 = x^3 - 3x^2(4) + 3x(4^2) - 4^3$

Now, calculate each term:

1. $x^3$ remains as $x^3$.
2. $-3x^2(4) = -12x^2$.
3. $3x(4^2) = 3x(16) = 48x$.
4. $-4^3 = -64$.

Thus, the expanded form is:

$x^3 - 12x^2 + 48x - 64$

From the expression in the image, the boxed values are:

• アイ = $12$
• ウエ = $48$
• オカ = $64$

Let me know if you'd like further clarification on this, or if you have other questions!

Here are some related questions to consider:

1. How does the binomial expansion formula work for larger powers?
2. What is the general form for $(x - a)^n$?
3. How do we expand expressions of the form $(ax + b)^n$?
4. What other methods can we use to expand $(x - 4)^3$?
5. How would the coefficients change if we expanded $(x + 4)^3$?

Tip: Always check for patterns in binomial expansions—they can simplify complex terms into recognizable sequences!