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The given expression is:

\[
8(x + 5) + 2(3x - 6)
\]

### Step 1: Expand both terms.

- First, distribute the \(8\) to both terms inside the parentheses:
  \[
  8(x + 5) = 8x + 40
  \]
  
- Next, distribute the \(2\) to both terms inside the second set of parentheses:
  \[
  2(3x - 6) = 6x - 12
  \]

### Step 2: Combine like terms.

Now, combine the expanded terms:
\[
8x + 40 + 6x - 12
\]

- Combine the \(x\)-terms:
  \[
  8x + 6x = 14x
  \]

- Combine the constant terms:
  \[
  40 - 12 = 28
  \]

### Final Answer:
\[
14x + 28
\]

Would you like any further details or have any questions?

Here are 5 related questions:
1. How would the result change if the coefficient of \(x + 5\) were 7 instead of 8?
2. What if the second term inside the parentheses was positive instead of negative?
3. How do we handle distribution when there are negative coefficients outside the parentheses?
4. Can this expression be factored further, and if so, how?
5. How does distribution change when working with variables raised to higher powers?

**Tip:** Always remember to distribute the coefficient to every term inside the parentheses when expanding expressions!

Learn how to expand and simplify the expression 8(x + 5) + 2(3x - 6) using the distributive property. This step-by-step guide helps students in Grades 7-9 understand key algebraic concepts and simplify expressions efficiently.

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