Math Problem Statement

أي الدوال التالية زوجي؟ (Which of the following functions is even?)

Solution

The question in the image asks: "Which of the following functions is even?" The functions provided are:

  • f(x)=x3f(x) = x^3 (B)
  • f(x)=1xf(x) = \frac{1}{x} (D)
  • f(x)=x2+xf(x) = x^2 + |x| (A)
  • f(x)=x2+xf(x) = x^2 + x (C)

To determine if a function is even:

A function f(x)f(x) is even if: f(x)=f(x) for all x.f(-x) = f(x) \text{ for all } x.

Now, let's test each function to see if it satisfies this condition:

  1. f(x)=x3f(x) = x^3:

    • f(x)=(x)3=x3f(-x) = (-x)^3 = -x^3, which is not equal to x3x^3. Therefore, this function is not even.
  2. f(x)=1xf(x) = \frac{1}{x}:

    • f(x)=1x=1xf(-x) = \frac{1}{-x} = -\frac{1}{x}, which is not equal to 1x\frac{1}{x}. Therefore, this function is not even.
  3. f(x)=x2+xf(x) = x^2 + |x|:

    • f(x)=(x)2+x=x2+xf(-x) = (-x)^2 + |-x| = x^2 + |x|. This is the same as f(x)f(x). Therefore, this function is even.
  4. f(x)=x2+xf(x) = x^2 + x:

    • f(x)=(x)2+(x)=x2xf(-x) = (-x)^2 + (-x) = x^2 - x, which is not equal to x2+xx^2 + x. Therefore, this function is not even.

Conclusion:

The correct answer is A\mathbf{A}, f(x)=x2+xf(x) = x^2 + |x|, which is an even function.

Would you like further clarification or additional details on how to test for even and odd functions?

Here are some related questions:

  1. How do you test if a function is odd?
  2. What are the general properties of even and odd functions?
  3. Can a function be both even and odd?
  4. What does the graph of an even function look like?
  5. How are absolute values involved in even functions?

Tip: Even functions are symmetric about the y-axis. This can help you quickly recognize them visually!

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Math Problem Analysis

Mathematical Concepts

Even and Odd Functions
Symmetry
Function Analysis

Formulas

f(-x) = f(x) (Condition for an even function)

Theorems

Even Function Theorem: A function is even if f(-x) = f(x) for all x.

Suitable Grade Level

High School