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We are given that \( g(x) = x^2 \). Let's solve each part:

### a) \( g(1) \)
\[
g(1) = 1^2 = 1
\]

### b) \( g(-2) \)
\[
g(-2) = (-2)^2 = 4
\]

### c) \( g(-x) \)
\[
g(-x) = (-x)^2 = x^2
\]

### d) \( g(2y) \)
\[
g(2y) = (2y)^2 = 4y^2
\]

### e) \( g(1+h) \)
\[
g(1+h) = (1+h)^2 = 1^2 + 2(1)(h) + h^2 = 1 + 2h + h^2
\]

If you have any questions or need further details, feel free to ask! Here are 5 related questions to expand your understanding:

1. What is the derivative of \( g(x) = x^2 \)?
2. How does \( g(-x) \) compare to \( g(x) \) in general?
3. Can you find \( g(a+b) \) for arbitrary constants \( a \) and \( b \)?
4. What happens to the function \( g(x) = x^2 \) as \( x \to \infty \)?
5. Can you find \( g(x^2) \) for any given \( x \)?

**Tip**: Always remember that squaring a negative value results in a positive number, as in part c where \( g(-x) = g(x) \).

Given that g(x) = x^2, find the following: a) g(1), b) g(-2), c) g(-x), d) g(2y), e) g(1+h).

Learn how to evaluate the quadratic function g(x) = x^2 for different inputs, including integers, variables, and expressions. This guide provides detailed solutions for g(1), g(-2), g(-x), g(2y), and g(1+h), covering key algebraic concepts.

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