f(x)=(x+5, x<-1) (-3x-2,x\ge1) find the answer for f(-1)

The function \( f(x) \) is defined piecewise as:

\[
f(x) =
\begin{cases} 
x + 5 & \text{if } x < -1 \\
-3x - 2 & \text{if } x \geq 1 
\end{cases}
\]

We are tasked with finding \( f(-1) \), but notice that the function is not directly defined for \( x = -1 \) since neither \( x < -1 \) nor \( x \geq 1 \) applies.

Thus, the function \( f(x) \) is undefined at \( x = -1 \).

Would you like to explore any of these related topics or other examples?

1. How to handle undefined values in piecewise functions.
2. Can a function be redefined to include points like \( x = -1 \)?
3. What are the differences between continuous and discontinuous functions?
4. How to graph piecewise functions and identify gaps.
5. Solving piecewise functions with different conditions.

**Tip**: Always check the domain of each piece in a piecewise function before plugging in values!

Learn how to evaluate a piecewise function and handle undefined values. In this problem, we explore f(x) with different conditions for x < -1 and x ≥ 1, and find that f(-1) is undefined. This example is perfect for students in Grades 9-11 working on function domains.

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