Math Problem Statement
إذا كانت \( f(x) = \begin{cases} x - 2, & x < 3 \\ x + 3, & x \geq 3 \end{cases} \) فإن \( f(2) \) تساوي
Solution
The piecewise function is defined as:
\begin{cases} x - 2, & x < 3 \\ x + 3, & x \geq 3 \end{cases}$$ We are asked to find $$f(2)$$. To determine $$f(2)$$, we need to check which part of the piecewise function applies when $$x = 2$$. Since $$2 < 3$$, we use the first part of the function, $$f(x) = x - 2$$. Substitute $$x = 2$$ into this part: $$f(2) = 2 - 2 = 0$$ ### Answer: $$f(2) = 0$$ Would you like a detailed explanation on piecewise functions or have any questions? ### Related Questions: 1. How do we evaluate a piecewise function for a given input? 2. What is the general method to determine which part of a piecewise function to use? 3. Can a piecewise function be continuous at the point where it switches? 4. How would we find $$f(3)$$ for this function? 5. What are the applications of piecewise functions in real-world scenarios? ### Tip: Always check the condition on $$x$$ to select the correct expression in a piecewise function before substituting values.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Piecewise functions
Function evaluation
Formulas
f(x) = x - 2 for x < 3
f(x) = x + 3 for x >= 3
Theorems
-
Suitable Grade Level
Grades 6-8
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