Math Problem Statement

𝑦=𝑥𝑒𝑥,𝑦=𝑒𝑥,𝑥=0,and𝑥=1

Solution

You’ve given two equations:

  1. y=xexy = x e^x
  2. y=exy = e^x

along with the conditions: x=0x = 0 and x=1x = 1. Based on the wording, it seems like you want to explore these two equations between the limits x=0x = 0 and x=1x = 1.

Let’s break it down:

1. Evaluating at x=0x = 0:

For the first equation y=xexy = x e^x, when x=0x = 0:

y=0×e0=0y = 0 \times e^0 = 0

For the second equation y=exy = e^x, when x=0x = 0:

y=e0=1y = e^0 = 1

2. Evaluating at x=1x = 1:

For the first equation y=xexy = x e^x, when x=1x = 1:

y=1×e1=ey = 1 \times e^1 = e

For the second equation y=exy = e^x, when x=1x = 1:

y=e1=ey = e^1 = e

Summary:

  • At x=0x = 0:

    • y=0y = 0 for y=xexy = x e^x
    • y=1y = 1 for y=exy = e^x
  • At x=1x = 1:

    • y=ey = e for y=xexy = x e^x
    • y=ey = e for y=exy = e^x

Let me know if you want to explore anything further like plotting or analyzing their behavior between x=0x = 0 and x=1x = 1, or anything else!


Here are a few related questions:

  1. How do the functions y=xexy = x e^x and y=exy = e^x compare on an interval like [0,1][0, 1]?
  2. What is the derivative of y=xexy = x e^x?
  3. How do exponential growth and multiplication by xx affect the behavior of these functions?
  4. Can you compute the area between the curves y=xexy = x e^x and y=exy = e^x over the interval [0,1][0, 1]?
  5. What is the general behavior of the function y=xexy = x e^x for larger values of xx?

Tip: When evaluating an exponential function like exe^x, remember that e0=1e^0 = 1, and the exponential function grows faster as xx increases.

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Math Problem Analysis

Mathematical Concepts

Exponential Functions
Function Evaluation
Limits

Formulas

y = x e^x
y = e^x

Theorems

Exponential Function Properties

Suitable Grade Level

Grades 10-12