Math Problem Statement

Evaluate the function f(x) = 4x^2 - 5x for the given values of x: (a) f(-3), (b) f(-2), (c) f(-1), (d) f(0), (e) f(1).

Solution

The problem asks to evaluate the function f(x)=4x25xf(x) = 4x^2 - 5x for different values of xx.

Let's solve each part:

f(x)=4x25xf(x) = 4x^2 - 5x

  1. (a) f(3)f(-3):

    f(3)=4(3)25(3)=4(9)+15=36+15=51f(-3) = 4(-3)^2 - 5(-3) = 4(9) + 15 = 36 + 15 = 51

  2. (b) f(2)f(-2):

    f(2)=4(2)25(2)=4(4)+10=16+10=26f(-2) = 4(-2)^2 - 5(-2) = 4(4) + 10 = 16 + 10 = 26

  3. (c) f(1)f(-1):

    f(1)=4(1)25(1)=4(1)+5=4+5=9f(-1) = 4(-1)^2 - 5(-1) = 4(1) + 5 = 4 + 5 = 9

  4. (d) f(0)f(0):

    f(0)=4(0)25(0)=0f(0) = 4(0)^2 - 5(0) = 0

  5. (e) f(1)f(1):

    f(1)=4(1)25(1)=4(1)5=45=1f(1) = 4(1)^2 - 5(1) = 4(1) - 5 = 4 - 5 = -1

Final answers:

  • (a) f(3)=51f(-3) = 51
  • (b) f(2)=26f(-2) = 26
  • (c) f(1)=9f(-1) = 9
  • (d) f(0)=0f(0) = 0
  • (e) f(1)=1f(1) = -1

Would you like more details on any step?

Here are 5 follow-up questions related to this topic:

  1. How would the function change if the coefficient of x2x^2 was altered?
  2. What is the significance of evaluating a quadratic function at different points?
  3. How does the vertex of a quadratic function affect its values?
  4. Can you graph this function based on these values?
  5. How does factoring the quadratic expression help in finding its roots?

Tip: The symmetry of quadratic functions can be used to quickly estimate values near the vertex.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Substitution

Formulas

f(x) = 4x^2 - 5x

Theorems

Quadratic Function Evaluation

Suitable Grade Level

Grades 9-10