Math Problem Statement

Use cylindrical coordinates to evaluate the triple integral ∭_E 5√(x^2 + y^2) dV, where E is the region that lies inside the cylinder x^2 + y^2 = 9 and between the planes z = -2 and z = 3.

Solution

To solve this problem, we are asked to evaluate the triple integral using cylindrical coordinates. Here's the detailed solution approach:

Step 1: Set up the Integral in Cylindrical Coordinates

Given: E5x2+y2dV\iiint_E 5\sqrt{x^2 + y^2} \, dV where EE is the region inside the cylinder x2+y2=9x^2 + y^2 = 9 and between the planes z=2z = -2 and z=3z = 3.

In cylindrical coordinates, we have:

  • x=rcosθx = r \cos \theta,
  • y=rsinθy = r \sin \theta,
  • z=zz = z,
  • x2+y2=r2x^2 + y^2 = r^2, so x2+y2=r\sqrt{x^2 + y^2} = r.

The volume element dVdV in cylindrical coordinates is dV=rdrdθdzdV = r \, dr \, d\theta \, dz.

Step 2: Rewrite the Integral

Substitute x2+y2=r\sqrt{x^2 + y^2} = r and dV=rdrdθdzdV = r \, dr \, d\theta \, dz into the integral: E5x2+y2dV=E5rrdrdθdz=E5r2drdθdz\iiint_E 5\sqrt{x^2 + y^2} \, dV = \iiint_E 5r \cdot r \, dr \, d\theta \, dz = \iiint_E 5r^2 \, dr \, d\theta \, dz

Step 3: Set up the Limits of Integration

For the region EE:

  • rr ranges from 00 to 33 (since x2+y2=9x^2 + y^2 = 9 gives r=3r = 3),
  • θ\theta ranges from 00 to 2π2\pi (full circle around the cylinder),
  • zz ranges from 2-2 to 33 (between the given planes).

So, the integral becomes: z=23θ=02πr=035r2drdθdz\int_{z=-2}^{3} \int_{\theta=0}^{2\pi} \int_{r=0}^{3} 5r^2 \, dr \, d\theta \, dz

Step 4: Evaluate the Integral

  1. Integrate with respect to rr: 035r2dr=503r2dr=5[r33]03=5273=59=45\int_{0}^{3} 5r^2 \, dr = 5 \int_{0}^{3} r^2 \, dr = 5 \left[ \frac{r^3}{3} \right]_{0}^{3} = 5 \cdot \frac{27}{3} = 5 \cdot 9 = 45

  2. Integrate with respect to θ\theta: 02π45dθ=452π=90π\int_{0}^{2\pi} 45 \, d\theta = 45 \cdot 2\pi = 90\pi

  3. Integrate with respect to zz: 2390πdz=90π[z]23=90π(3+2)=90π5=450π\int_{-2}^{3} 90\pi \, dz = 90\pi \cdot \left[ z \right]_{-2}^{3} = 90\pi \cdot (3 + 2) = 90\pi \cdot 5 = 450\pi

Final Answer

E5x2+y2dV=450π\iiint_E 5\sqrt{x^2 + y^2} \, dV = 450\pi

Would you like further details on any specific part of this solution?


Here are five related questions you might find interesting:

  1. How do cylindrical coordinates simplify integration for circular regions?
  2. Why is dV=rdrdθdzdV = r \, dr \, d\theta \, dz in cylindrical coordinates?
  3. How would this problem change if we were given spherical coordinates instead?
  4. What is the significance of choosing cylindrical coordinates for a cylinder-shaped region?
  5. How does the integration process change when the function being integrated is not symmetric?

Tip: For problems involving circular or cylindrical symmetry, cylindrical coordinates often simplify the integration process, reducing complexity and making the setup more intuitive.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Triple Integrals
Cylindrical Coordinates

Formulas

Cylindrical coordinates: x = r cos(θ), y = r sin(θ), z = z
Volume element in cylindrical coordinates: dV = r dr dθ dz

Theorems

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Suitable Grade Level

College