To solve for $f(-2)$ when $f(x) = x^2 - 2x + 5$, we simply substitute $x = -2$ into the function:

$f(-2) = (-2)^2 - 2(-2) + 5$

Step-by-step:

1. $(-2)^2 = 4$
2. $-2(-2) = 4$
3. So, $f(-2) = 4 + 4 + 5 = 13$

Thus, $f(-2) = 13$.

Would you like more details or have any questions? Here are 5 related questions:

1. What is the vertex of the function $f(x) = x^2 - 2x + 5$?
2. How do you find the axis of symmetry for a quadratic function?
3. What is the minimum value of the function $f(x) = x^2 - 2x + 5$?
4. How does completing the square help in analyzing quadratic functions?
5. How would you graph $f(x) = x^2 - 2x + 5$?

Tip: When evaluating functions at specific points, always substitute carefully and simplify each term step-by-step to avoid errors.