To solve the function $f(x) = x^2 + 2x - 2$ at $x = -1$, we substitute $x = -1$ into the function:

$f(-1) = (-1)^2 + 2(-1) - 2$

Now, let's calculate this step by step:

1. $(-1)^2 = 1$
2. $2(-1) = -2$
3. Therefore, $f(-1) = 1 - 2 - 2$

Simplifying further:

$f(-1) = 1 - 4 = -3$

So, the value of the function $f(x)$ when $x = -1$ is $f(-1) = -3$.

Would you like further details on this calculation, or do you have any other questions?

Here are 8 related questions:

1. What is the function value at $x = 0$?
2. How does the value change if $x = 1$?
3. Can you find the derivative of $f(x)$ and evaluate it at $x = -1$?
4. What is the significance of the vertex of the parabola represented by $f(x)$?
5. How would the function behave for very large positive or negative values of $x$?
6. What are the roots of the function $f(x) = 0$?
7. How would you rewrite $f(x)$ by completing the square?
8. What is the range of the function $f(x)$?

Tip: Evaluating functions at specific points is a common way to understand their behavior locally, especially when analyzing graphs.