To find $f(0)$ for the function $f(x) = 4x^2 + 2x + 3$, substitute $x = 0$ into the equation:

$f(0) = 4(0)^2 + 2(0) + 3$

Simplifying:

$f(0) = 0 + 0 + 3 = 3$

Thus, $f(0) = 3$.

Would you like more details, or do you have any questions?

Here are 5 related questions:

1. What is $f(1)$ for the same function?
2. How do you find the vertex of the quadratic function $f(x) = 4x^2 + 2x + 3$?
3. What is the derivative of $f(x) = 4x^2 + 2x + 3$?
4. Can you factor $f(x) = 4x^2 + 2x + 3$?
5. How does the graph of $f(x) = 4x^2 + 2x + 3$ look?

Tip: To evaluate functions at specific values, simply substitute the given value of $x$ into the equation.