Math Problem Statement

Evaluate the function f(x) = 2x² - 3x + 1 for x = 3.

Solution

To evaluate the function f(x)=2x23x+1f(x) = 2x^2 - 3x + 1 for x=3x = 3, follow these steps:

  1. Substitute x=3x = 3 into the function: f(3)=2(3)23(3)+1f(3) = 2(3)^2 - 3(3) + 1

  2. Calculate 323^2: 32=93^2 = 9

  3. Multiply by 2: 2×9=182 \times 9 = 18

  4. Multiply 3-3 by 3: 3×3=9-3 \times 3 = -9

  5. Add the results: f(3)=189+1=10f(3) = 18 - 9 + 1 = 10

So, f(3)=10f(3) = 10.

Would you like more details or have any questions?

Here are some related questions:

  1. What is the value of f(x)=2x23x+1f(x) = 2x^2 - 3x + 1 when x=1x = -1?
  2. How does the graph of f(x)=2x23x+1f(x) = 2x^2 - 3x + 1 look?
  3. What is the vertex of the function f(x)=2x23x+1f(x) = 2x^2 - 3x + 1?
  4. For what values of xx does f(x)=0f(x) = 0?
  5. How does changing the coefficient of x2x^2 in the function affect its graph?

Tip: When evaluating functions, substitute the given value of xx carefully, and follow the order of operations: parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right).

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions

Formulas

Quadratic function formula f(x) = ax^2 + bx + c

Theorems

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Suitable Grade Level

Grades 7-9