Math Problem Statement

Evaluate log_5(1).

Solution

The problem asks to evaluate log5(1)\log_{5}(1).

The logarithmic expression loga(b)\log_{a}(b) represents the power to which the base aa must be raised to yield bb. Specifically:

log5(1)=x    5x=1\log_{5}(1) = x \implies 5^x = 1

The only value of xx that satisfies 5x=15^x = 1 is x=0x = 0, because any number raised to the power of 0 equals 1.

Thus: log5(1)=0\log_{5}(1) = 0

Do you have any questions or want further clarification?


Here are 5 related questions to consider:

  1. How is the logarithmic function defined for negative bases?
  2. Why does loga(1)=0\log_a(1) = 0 for any positive base a1a \neq 1?
  3. How do you simplify logarithmic expressions with different bases?
  4. What happens when loga(ax)\log_a(a^x) is evaluated?
  5. Can the base of a logarithm be a fraction or a decimal?

Tip: Always check the base and argument of the logarithmic function to ensure they meet the logarithm's domain conditions (base > 0 and base ≠ 1; argument > 0).

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponential Functions

Formulas

log_a(b) = x implies a^x = b

Theorems

Any number raised to the power of 0 equals 1.

Suitable Grade Level

Grades 8-10