Math Problem Statement

log3 9\log3\text{ }9

Solution

The expression log39\log_3 9 represents the logarithm of 9 with base 3.

Solution:

We are solving for xx in the equation: log39=x    3x=9\log_3 9 = x \implies 3^x = 9

Step 1: Rewrite 9 as a power of 3

9=329 = 3^2

Step 2: Substitute into the equation

3x=323^x = 3^2

Step 3: Equating exponents

Since the bases are the same, the exponents must also be equal: x=2x = 2

Final Answer:

log39=2\log_3 9 = 2

Would you like a more detailed explanation or have further questions?


Here are 5 related questions:

  1. What is log327\log_3 27?
  2. How do you evaluate log381\log_3 81?
  3. How would you compute log31\log_3 1?
  4. What is the relationship between logarithms and exponents?
  5. How do you simplify log3(39)\log_3 (3 \cdot 9)?

Tip: Always try rewriting numbers in terms of the base for easier logarithmic evaluations!

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponents
Properties of Logarithms

Formulas

\( \log_b a = x \iff b^x = a \)

Theorems

Logarithmic-Exponential Relationship

Suitable Grade Level

Grades 8-10