Math Problem Statement

The graph of the function f(x) is given. Answer the questions about f(a), lim(x→a) f(x), and continuity at different values of a.

Solution

Let's analyze the graph of f(x)f(x) to answer the questions in the table. We are tasked with filling in the values for f(a)f(a), limxaf(x)\lim_{x \to a} f(x), and whether f(x)f(x) is continuous at the given values of aa.

Step-by-step:

  1. For a=5a = -5:

    • f(a)f(a): At x=5x = -5, the graph has a point at y=3y = 3, so f(5)=3f(-5) = 3.
    • limx5f(x)\lim_{x \to -5} f(x): As xx approaches -5 from both sides, the value approaches 33, so limx5f(x)=3\lim_{x \to -5} f(x) = 3.
    • Continuity: Since f(5)=3f(-5) = 3 and the limit exists and equals 33, the function is continuous at x=5x = -5.
  2. For a=2a = -2:

    • f(a)f(a): At x=2x = -2, the graph shows a hole (open circle) at y=0y = 0, so f(2)f(-2) does not exist, i.e., f(2)=DNEf(-2) = \text{DNE}.
    • limx2f(x)\lim_{x \to -2} f(x): As xx approaches -2 from both sides, the value approaches 00, so limx2f(x)=0\lim_{x \to -2} f(x) = 0.
    • Continuity: Since f(2)f(-2) does not exist, the function is not continuous at x=2x = -2.
  3. For a=0a = 0:

    • f(a)f(a): At x=0x = 0, the graph passes through y=2y = 2, so f(0)=2f(0) = 2.
    • limx0f(x)\lim_{x \to 0} f(x): As xx approaches 0 from both sides, the value approaches 22, so limx0f(x)=2\lim_{x \to 0} f(x) = 2.
    • Continuity: Since f(0)=2f(0) = 2 and the limit exists and equals 22, the function is continuous at x=0x = 0.
  4. For a=1a = 1:

    • f(a)f(a): At x=1x = 1, the graph has a point at y=3y = -3, so f(1)=3f(1) = -3.
    • limx1f(x)\lim_{x \to 1} f(x): As xx approaches 1 from both sides, the value approaches 3-3, so limx1f(x)=3\lim_{x \to 1} f(x) = -3.
    • Continuity: Since f(1)=3f(1) = -3 and the limit exists and equals 3-3, the function is continuous at x=1x = 1.
  5. For a=3a = 3:

    • f(a)f(a): At x=3x = 3, the graph shows a hole (open circle) at y=4y = -4, so f(3)f(3) does not exist, i.e., f(3)=DNEf(3) = \text{DNE}.
    • limx3f(x)\lim_{x \to 3} f(x): As xx approaches 3 from both sides, the value approaches 4-4, so limx3f(x)=4\lim_{x \to 3} f(x) = -4.
    • Continuity: Since f(3)f(3) does not exist, the function is not continuous at x=3x = 3.

Completed Table:

aaf(a)f(a)limxaf(x)\lim_{x \to a} f(x)Is f(x)f(x) continuous at x=ax = a?
-533Yes
-2DNE0No
022Yes
1-3-3Yes
3DNE-4No

Let me know if you'd like further explanations!


5 Related Questions:

  1. What are the criteria for continuity at a point?
  2. How do we calculate limits from a graph?
  3. What is the relationship between a limit and the value of a function at a point?
  4. How do removable discontinuities appear in graphs?
  5. Can a function be continuous if the limit does not exist at a point?

Tip: Always check for holes or jumps in the graph when determining continuity.

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Math Problem Analysis

Mathematical Concepts

Limits
Continuity
Function Evaluation
Graphs of Functions

Formulas

Limit Definition: lim(x→a) f(x)
Continuity: A function is continuous at a point if f(a) exists, lim(x→a) f(x) exists, and f(a) = lim(x→a) f(x)

Theorems

Limit Theorem
Continuity at a Point Theorem

Suitable Grade Level

Grades 11-12 (Pre-Calculus or Calculus)