Math Problem Statement
Solution
We are tasked with evaluating the following limit:
Let us break this problem into steps:
Step 1: Approximation of
Near , we use the Taylor series approximation:
Step 2: Expand and
Using binomial expansions:
-
For :
-
For : [ \sqrt[3]{\cos x} \approx \sqrt[3]{1 - \frac{x^2}{2}} \approx 1 - \frac{x^2}{6}. ]
Step 3: Simplify the numerator
Simplify further:
Step 4: Approximation of
Near , . Thus:
Step 5: Simplify the fraction
Substitute into the limit:
Simplify:
Step 6: Evaluate the limit
As , the limit is:
Final Answer:
Would you like a detailed explanation of any specific step? Here are some related questions to expand understanding:
- How do Taylor series expansions help in solving limits involving trigonometric functions?
- Can the same technique be applied to other similar problems involving higher-order roots?
- What is the justification for approximating near zero?
- How does the binomial theorem aid in expanding functions near their base values?
- Could L’Hôpital’s Rule be used to evaluate this limit instead?
Tip: When solving trigonometric limits, remember that Taylor approximations and simplifications near small angles () are often the most efficient methods
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Limits
Trigonometric Functions
Taylor Series
Binomial Expansion
Formulas
cos x ≈ 1 - x^2/2
sqrt(cos x) ≈ 1 - x^2/4
cube root(cos x) ≈ 1 - x^2/6
sin^2 x ≈ x^2
Theorems
Taylor Series Approximation
Binomial Theorem
Suitable Grade Level
Grades 11-12
Related Recommendation
Evaluate the Limit of (1 - sqrt(cos x)) / x as x Approaches 0
Calculate Limit of (cos(3x) - cos(x))/(x^2 sqrt(4 - x)) as x Approaches 0
Limit of (cos(x^2) - 1) / (sin(x))^4 as x Approaches 0
Evaluating Limit of a Trigonometric Function Using Small-Angle Approximation
Evaluate lim x->0+ [cos(2x)]^(1/x^2) Using Taylor Series and Logarithmic Approach