Math Problem Statement

What is the value of $\lim\limits_{x\to 3}\frac{x^4 -9x^2 + 4x - 12}{(x-3)(4-x)}?$ Could you please use the specific LaTeX math mode delimiters for your response? LaTex math mode specific delimiters as following inline math mode : ( and ) display math mode: insert linebreak after opening $$,…

Solution

To evaluate the limit

limx3x49x2+4x12(x3)(4x),\lim_{x \to 3} \frac{x^4 - 9x^2 + 4x - 12}{(x-3)(4-x)},

let's proceed step by step.

Step 1: Factorize the numerator x49x2+4x12x^4 - 9x^2 + 4x - 12

The numerator is a polynomial of degree 4. We use grouping and substitution to simplify. Rewrite x49x2+4x12x^4 - 9x^2 + 4x - 12 as:

x49x2+4x12=x49x2+(4x12).x^4 - 9x^2 + 4x - 12 = x^4 - 9x^2 + (4x - 12).

Notice that x49x2x^4 - 9x^2 is a difference of squares:

x49x2=(x2)2(3x)2=(x23x)(x2+3x).x^4 - 9x^2 = (x^2)^2 - (3x)^2 = (x^2 - 3x)(x^2 + 3x).

Thus, the numerator becomes:

x49x2+4x12=(x23x)(x2+3x)+4(x3).x^4 - 9x^2 + 4x - 12 = (x^2 - 3x)(x^2 + 3x) + 4(x - 3).

Now, group terms involving x3x - 3:

(x23x)(x2+3x)+4(x3)=(x3)[(x2+3x)+4].(x^2 - 3x)(x^2 + 3x) + 4(x - 3) = (x - 3)[(x^2 + 3x) + 4].

Simplify inside the bracket:

x2+3x+4.x^2 + 3x + 4.

So, the numerator factors as:

x49x2+4x12=(x3)(x2+3x+4).x^4 - 9x^2 + 4x - 12 = (x - 3)(x^2 + 3x + 4).

Step 2: Simplify the expression

The denominator is (x3)(4x)(x-3)(4-x). Therefore, the fraction becomes:

x49x2+4x12(x3)(4x)=(x3)(x2+3x+4)(x3)(4x).\frac{x^4 - 9x^2 + 4x - 12}{(x-3)(4-x)} = \frac{(x - 3)(x^2 + 3x + 4)}{(x-3)(4-x)}.

Cancel out the common factor x3x - 3 (valid as x3x \to 3):

(x3)(x2+3x+4)(x3)(4x)=x2+3x+44x.\frac{(x - 3)(x^2 + 3x + 4)}{(x-3)(4-x)} = \frac{x^2 + 3x + 4}{4 - x}.

Step 3: Evaluate the limit as x3x \to 3

Substitute x=3x = 3 into the simplified expression:

x2+3x+44x=32+3(3)+443.\frac{x^2 + 3x + 4}{4 - x} = \frac{3^2 + 3(3) + 4}{4 - 3}.

Simplify the numerator and denominator:

Numerator: 32+3(3)+4=9+9+4=22,\text{Numerator: } 3^2 + 3(3) + 4 = 9 + 9 + 4 = 22, Denominator: 43=1.\text{Denominator: } 4 - 3 = 1.

Thus:

x2+3x+44x=221=22.\frac{x^2 + 3x + 4}{4 - x} = \frac{22}{1} = 22.

Final Answer:

limx3x49x2+4x12(x3)(4x)=22.\lim_{x \to 3} \frac{x^4 - 9x^2 + 4x - 12}{(x-3)(4-x)} = 22.

Would you like further clarification or additional steps explained? Here are five related questions for deeper understanding:

  1. How does the cancellation of terms work in limits, and why is it valid?
  2. Can the numerator x49x2+4x12x^4 - 9x^2 + 4x - 12 be factored differently for other roots?
  3. What is the role of the difference of squares in simplifying polynomial expressions?
  4. Why is it important to verify if a term approaches 0 before canceling it in a fraction?
  5. How would the limit change if the denominator were slightly altered?

Tip: Always check the domain of the function and ensure no division by zero before simplifying limits.

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Math Problem Analysis

Mathematical Concepts

Limits
Polynomial Factorization
Difference of Squares

Formulas

\( (a^2 - b^2) = (a - b)(a + b) \)
Limit evaluation by substitution

Theorems

Limit Laws
Difference of Squares Theorem

Suitable Grade Level

Grades 11-12