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The given integral is:

\[
\int_1^9 \frac{1}{\sqrt{x}(1 + \sqrt{x})} \, dx
\]

To solve this, we can make a substitution to simplify the expression.

### Step 1: Substitution

Let \( u = \sqrt{x} \), which implies that \( x = u^2 \) and \( dx = 2u \, du \).

Now, when \( x = 1 \), \( u = 1 \), and when \( x = 9 \), \( u = 3 \).

Substitute \( x = u^2 \) into the integral:

\[
\int_1^9 \frac{1}{\sqrt{x}(1 + \sqrt{x})} \, dx = \int_1^3 \frac{1}{u(1 + u)} \cdot 2u \, du
\]

### Step 2: Simplifying

The \( u \) terms simplify:

\[
2 \int_1^3 \frac{1}{1 + u} \, du
\]

### Step 3: Integration

The integral of \( \frac{1}{1 + u} \) is \( \ln(1 + u) \). Thus, we get:

\[
2 \left[ \ln(1 + u) \right]_1^3
\]

### Step 4: Evaluate the Limits

Now, evaluate the definite integral:

\[
2 \left[ \ln(1 + 3) - \ln(1 + 1) \right] = 2 \left[ \ln(4) - \ln(2) \right]
\]

Using the logarithmic identity \( \ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right) \), we get:

\[
2 \ln\left(\frac{4}{2}\right) = 2 \ln(2)
\]

Finally, this simplifies to:

\[
2 \ln(2)
\]

### Final Answer:

The value of the integral is:

\[
2 \ln(2)
\]

Would you like further clarification or details on any of the steps?

Here are 5 related questions to expand your understanding:

1. How do logarithmic properties help simplify integrals?
2. Can we apply a similar substitution for other forms of integrals?
3. What is the geometric interpretation of the logarithmic function in this context?
4. How would this integral change if the limits of integration were different?
5. What are the conditions under which substitution is a helpful method for solving integrals?

**Tip:** Always check if a substitution will simplify both the differential and the integrand before proceeding with it.

Evaluate the integral: ∫[1,9] 1/(√x(1 + √x)) dx

Step-by-step solution for evaluating the integral ∫[1,9] 1/(√x(1 + √x)) dx. This problem involves the substitution method, logarithmic integration, and properties of logarithms. Suitable for undergraduate calculus students.

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