The given function is $h(x) = -2x - 3$. We are asked to find $h(6)$.

To do this, substitute $x = 6$ into the function:

$h(6) = -2(6) - 3$

$h(6) = -12 - 3$

$h(6) = -15$

Thus, $h(6) = -15$.

Would you like a more detailed explanation?

Here are 5 related questions for practice:

1. What is $h(8)$ if $h(x) = -2x - 3$?
2. If $h(x) = 3x + 4$, what is $h(6)$?
3. What is the value of $h(-3)$ in the function $h(x) = -2x - 3$?
4. Find $h(0)$ for the same function $h(x) = -2x - 3$.
5. How does changing the coefficient of $x$ in the function $h(x)$ affect the output?

Tip: When evaluating a function at a specific point, simply substitute the value into the equation for the variable.