Given h, of, x, equals, minus, 2, x, minus, 3h(x)=−2x−3, find h, of, 6h(6).

The given function is \( h(x) = -2x - 3 \). We are asked to find \( h(6) \).

To do this, substitute \( x = 6 \) into the function:

\[
h(6) = -2(6) - 3
\]

\[
h(6) = -12 - 3
\]

\[
h(6) = -15
\]

Thus, \( h(6) = -15 \).

Would you like a more detailed explanation? 

Here are 5 related questions for practice:
1. What is \( h(8) \) if \( h(x) = -2x - 3 \)?
2. If \( h(x) = 3x + 4 \), what is \( h(6) \)?
3. What is the value of \( h(-3) \) in the function \( h(x) = -2x - 3 \)?
4. Find \( h(0) \) for the same function \( h(x) = -2x - 3 \).
5. How does changing the coefficient of \( x \) in the function \( h(x) \) affect the output?

**Tip:** When evaluating a function at a specific point, simply substitute the value into the equation for the variable.

Learn how to evaluate the linear function h(x) = −2x − 3 at x = 6. This step-by-step solution explains function evaluation, substitution, and the importance of understanding linear equations. Suitable for students in Grades 6-8.

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