To complete the table for the function $h(x) = -3x - 1$, we need to evaluate the function for each given value of $x$. Here's the step-by-step calculation:

1. For $x = -3$: $h(-3) = -3(-3) - 1 = 9 - 1 = 8$

2. For $x = 8$: $h(8) = -3(8) - 1 = -24 - 1 = -25$

3. For $x = -2$: $h(-2) = -3(-2) - 1 = 6 - 1 = 5$

4. For $x = -1$: $h(-1) = -3(-1) - 1 = 3 - 1 = 2$

5. For $x = 2$: $h(2) = -3(2) - 1 = -6 - 1 = -7$

6. For $x = 0$: $h(0) = -3(0) - 1 = 0 - 1 = -1$

7. For $x = -1$ (again): $h(-1) = 2 \quad (\text{calculated earlier})$

8. For $x = 1$: $h(1) = -3(1) - 1 = -3 - 1 = -4$

9. For $x = 2$ (again): $h(2) = -7 \quad (\text{calculated earlier})$

10. For $x = 3$: $h(3) = -3(3) - 1 = -9 - 1 = -10$

11. For $x = -10$: $h(-10) = -3(-10) - 1 = 30 - 1 = 29$

Here’s the completed table:

x	h(x) = −3x − 1
-3	8
8	-25
-2	5
-1	2
2	-7
0	-1
-1	2
1	-4
2	-7
3	-10
-10	29

Would you like any further clarification or examples? Here are some related questions:

1. How would the graph of this function look?
2. What is the slope and y-intercept of the equation $h(x) = -3x - 1$?
3. How do we solve for $x$ when given $h(x) = 0$?
4. What happens to the function when $x$ increases?
5. How would the table look if the function were $h(x) = 2x + 5$?

Tip: When evaluating a linear function like this one, just substitute the $x$-values into the formula, and remember the general form $y = mx + b$ for slopes and intercepts!