Math Problem Statement

Complete the table for the function f(s) = |s + 2|, where s values are -7, -5, -3, and -1.

Solution

To complete the table based on the function f(s)=s+2f(s) = |s + 2|, we calculate f(s)f(s) for each value of ss.

Step-by-step calculations:

  1. For s=7s = -7: f(7)=7+2=5=5f(-7) = |-7 + 2| = |-5| = 5
  2. For s=5s = -5: f(5)=5+2=3=3f(-5) = |-5 + 2| = |-3| = 3
  3. For s=3s = -3: f(3)=3+2=1=1f(-3) = |-3 + 2| = |-1| = 1
  4. For s=1s = -1: f(1)=1+2=1=1f(-1) = |-1 + 2| = |1| = 1

The completed table:

| ss | f(s)=s+2f(s) = |s + 2| | |----------|----------------------| | 7-7 | 55 | | 5-5 | 33 | | 3-3 | 11 | | 1-1 | 11 |

Would you like more details or have any questions?

Here are some related questions for practice:

  1. What is f(0)f(0) for the function f(s)=s+2f(s) = |s + 2|?
  2. How does the function f(s)=s+2f(s) = |s + 2| behave for positive values of ss?
  3. What is the graphical representation of the function f(s)=s+2f(s) = |s + 2|?
  4. How do you solve equations involving absolute values like f(s)=4f(s) = 4?
  5. What is the domain and range of the function f(s)=s+2f(s) = |s + 2|?

Tip: When dealing with absolute value functions, remember that they always produce non-negative results regardless of the input.

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Math Problem Analysis

Mathematical Concepts

Absolute Value
Function Evaluation

Formulas

f(s) = |s + 2|

Theorems

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Suitable Grade Level

Grades 6-8