Math Problem Statement

For f(x) = |x| + 2, then f(-2) = 0. True or False?

Solution

Let's analyze the question.

The given function is:

f(x)=x+2f(x) = |x| + 2

You are tasked with determining whether f(2)=0f(-2) = 0 is true or false.

Step 1: Evaluate f(2)f(-2)

Substitute x=2x = -2 into the function:

f(2)=2+2f(-2) = |-2| + 2

The absolute value of 2-2 is 22. So:

f(2)=2+2=4f(-2) = 2 + 2 = 4

Step 2: Check if f(2)=0f(-2) = 0

Clearly, f(2)=4f(-2) = 4, which is not equal to 0.

Conclusion:

The statement f(2)=0f(-2) = 0 is false.

Let me know if you'd like a detailed explanation or have any follow-up questions! Here are some related questions to consider:

  1. What is the range of the function f(x)=x+2f(x) = |x| + 2?
  2. How does the absolute value function influence the graph of f(x)f(x)?
  3. What are the x-values that make f(x)=4f(x) = 4?
  4. Can f(x)=0f(x) = 0 for any real xx?
  5. How would the function change if f(x)=x2f(x) = |x| - 2?

Tip: When working with absolute value functions, always simplify the absolute value expression before applying further operations!

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Math Problem Analysis

Mathematical Concepts

Absolute Value Functions
Basic Algebra

Formulas

f(x) = |x| + 2

Theorems

Properties of Absolute Value

Suitable Grade Level

Grades 7-9