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We are given two functions, \( f(x) = 2x^2 - 1 \) and \( g(x) = 2x + 1 \), and we are asked to evaluate \( f(g(x)) \) when \( x = -3 \).

### Step 1: Evaluate \( g(x) \) at \( x = -3 \)
Using the function \( g(x) = 2x + 1 \):

\[
g(-3) = 2(-3) + 1 = -6 + 1 = -5
\]

### Step 2: Evaluate \( f(x) \) at \( x = -5 \)
Now, substitute \( g(-3) = -5 \) into \( f(x) = 2x^2 - 1 \):

\[
f(-5) = 2(-5)^2 - 1 = 2(25) - 1 = 50 - 1 = 49
\]

Thus, \( f(g(-3)) = 49 \).

The correct answer is **49**.

Would you like more details or have any questions?

Here are some related questions you might find helpful:
1. How do you evaluate compositions of functions?
2. What are common mistakes when working with function compositions?
3. Can you explain how to graph the composition of functions?
4. How does the domain of a function affect its composition?
5. How do you reverse a composition of functions?

**Tip**: Always evaluate the inner function first when working with compositions.

If f(x) = 2x^2 - 1 and g(x) = 2x + 1, evaluate f(g(x)) when x = -3.

Learn how to evaluate the composition of functions with f(x) = 2x^2 - 1 and g(x) = 2x + 1. This step-by-step guide shows the process for finding f(g(x)) when x = -3, suitable for Grades 9-10.

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