Math Problem Statement

Evaluate the expression. 1× 1 5 – 2 5 × 1 4

Solution

Let’s evaluate the given expression:

1×1525×141 \times \frac{1}{5} - \frac{2}{5} \times \frac{1}{4}

Step 1: Simplify each term

  • 1×15=151 \times \frac{1}{5} = \frac{1}{5}
  • 25×14=220=110\frac{2}{5} \times \frac{1}{4} = \frac{2}{20} = \frac{1}{10}

Step 2: Perform subtraction

Now subtract the two fractions: 15110\frac{1}{5} - \frac{1}{10}

Find a common denominator for 55 and 1010, which is 1010: 15=210\frac{1}{5} = \frac{2}{10}

So, 210110=110\frac{2}{10} - \frac{1}{10} = \frac{1}{10}

Final Answer:

110\boxed{\frac{1}{10}}

Would you like further clarification or another example?


Questions:

  1. How do you handle multiplication of fractions?
  2. What are common denominators, and why are they needed?
  3. Can subtraction of fractions ever result in a whole number?
  4. How would this change if the second term were addition instead of subtraction?
  5. How can this calculation be useful in real-world scenarios?

Tip:

Always simplify fractions at each step to avoid unnecessary complexity!

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Math Problem Analysis

Mathematical Concepts

Arithmetic
Fraction Operations
Simplification of Fractions

Formulas

a × b = (numerator₁ × numerator₂) / (denominator₁ × denominator₂)
a/b - c/d = (ad - bc) / bd

Theorems

Fundamental Theorem of Fractions (common denominator for addition/subtraction)

Suitable Grade Level

Grades 6-8