Math Problem Statement
Evaluate the expression. 1× 1 5 – 2 5 × 1 4
Solution
Let’s evaluate the given expression:
Step 1: Simplify each term
Step 2: Perform subtraction
Now subtract the two fractions:
Find a common denominator for and , which is :
So,
Final Answer:
Would you like further clarification or another example?
Questions:
- How do you handle multiplication of fractions?
- What are common denominators, and why are they needed?
- Can subtraction of fractions ever result in a whole number?
- How would this change if the second term were addition instead of subtraction?
- How can this calculation be useful in real-world scenarios?
Tip:
Always simplify fractions at each step to avoid unnecessary complexity!
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Math Problem Analysis
Mathematical Concepts
Arithmetic
Fraction Operations
Simplification of Fractions
Formulas
a × b = (numerator₁ × numerator₂) / (denominator₁ × denominator₂)
a/b - c/d = (ad - bc) / bd
Theorems
Fundamental Theorem of Fractions (common denominator for addition/subtraction)
Suitable Grade Level
Grades 6-8