https://file.aiquickdraw.com/mathbot/file/17304222241371t8il19y.jpg

The question asks you to evaluate \( f(2) \) for the function \( f(x) = \sqrt{2x + 1} \).

To solve this, follow these steps:

1. Substitute \( x = 2 \) into the function \( f(x) = \sqrt{2x + 1} \).
   
   \[
   f(2) = \sqrt{2(2) + 1}
   \]

2. Simplify inside the square root:

   \[
   f(2) = \sqrt{4 + 1} = \sqrt{5}
   \]

So, the answer is:
\[
f(2) = \sqrt{5}
\]

Would you like further details on how to evaluate functions like this? 

Here are 5 related questions to deepen your understanding:
1. How would you find \( f(3) \) for the function \( f(x) = \sqrt{2x + 1} \)?
2. What does the domain of \( f(x) = \sqrt{2x + 1} \) look like?
3. Can you evaluate \( f(-1) \) for this function, and if not, why?
4. How would you find the inverse of the function \( f(x) = \sqrt{2x + 1} \)?
5. How would you graph \( f(x) = \sqrt{2x + 1} \) on a coordinate plane?

**Tip:** When evaluating functions, always start by substituting the given value for \( x \) and simplifying step-by-step.

Solve the function f(x) = √(2x + 1) by finding f(2) with a detailed solution. This exercise covers fundamental function evaluation using substitution and square root operations, suitable for students in Grades 9-10.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation