Math Problem Statement

Evaluate the function. Round your answer to four decimal places, if necessary.

f⁡(x)=2.3⁢e2⁢x-0.1 ,   for f⁡(2).

f⁡(2)=

Solution

To evaluate the function f(x)=2.3e2x0.1f(x) = 2.3e^{2x - 0.1} at x=2x = 2:

Step 1: Substitute x=2x = 2 into the function:

f(2)=2.3e2(2)0.1f(2) = 2.3e^{2(2) - 0.1}

Step 2: Simplify the exponent:

2(2)0.1=40.1=3.92(2) - 0.1 = 4 - 0.1 = 3.9 f(2)=2.3e3.9f(2) = 2.3e^{3.9}

Step 3: Compute e3.9e^{3.9}:

Using a calculator or computational tool: e3.949.402449e^{3.9} \approx 49.402449

Step 4: Multiply by 2.3:

f(2)=2.3×49.402449113.6256f(2) = 2.3 \times 49.402449 \approx 113.6256

Final Answer:

f(2)113.6256f(2) \approx 113.6256

Let me know if you would like more details or have any questions! Here are some related queries for further exploration:

  1. What is the derivative of f(x)=2.3e2x0.1f(x) = 2.3e^{2x - 0.1}?
  2. How does the value of f(x)f(x) change as xx \to \infty?
  3. Evaluate f(x)f(x) for other values of xx, such as x=1x = 1 or x=0x = 0.
  4. Can we rewrite f(x)f(x) in terms of logarithmic functions?
  5. How is f(x)f(x) affected if the constant 2.32.3 changes to another value?

Tip: When working with exponential functions, ensure your calculator is in the correct mode to handle ee-based calculations.

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Math Problem Analysis

Mathematical Concepts

Exponential Functions
Substitution
Scientific Notation

Formulas

f(x) = ae^{bx+c}
e^x (natural exponential function)

Theorems

Properties of Exponential Functions

Suitable Grade Level

Grades 9-12