Math Problem Statement

Evaluate [\sqrt[\leftroot{-2}\uproot{2}\scriptstyle 3]{-125}].

Solution

The expression you provided is 1253\sqrt[3]{-125}, which represents the cube root of 125-125.

To solve this, we can express 125-125 as:

125=53-125 = -5^3

Since the cube root and the cube are inverse operations, the cube root of 53-5^3 is simply 5-5:

1253=5\sqrt[3]{-125} = -5

Thus, the value of 1253\sqrt[3]{-125} is 5-5.

Would you like further details or explanations on this?

Here are 5 related questions for further practice:

  1. What is 273\sqrt[3]{27}?
  2. How do you find 643\sqrt[3]{-64}?
  3. Can cube roots of negative numbers always be real?
  4. What is the cube root of 88?
  5. Simplify 83+643\sqrt[3]{-8} + \sqrt[3]{64}.

Tip: Cube roots of negative numbers are real because odd roots of negative numbers are negative.

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Math Problem Analysis

Mathematical Concepts

Cube Roots
Negative Numbers
Exponentiation

Formulas

\(\sqrt[3]{x} = x^{1/3}\)
\(x^n\) where n is an integer

Theorems

Cube Root Theorem (Odd roots of negative numbers are negative)
Exponentiation

Suitable Grade Level

Grades 8-10