To evaluate \(6^{-2}\), we need to apply the property of negative exponents, which states:

\[
a^{-n} = \frac{1}{a^n}
\]

So, for \(6^{-2}\):

\[
6^{-2} = \frac{1}{6^2}
\]

Next, we calculate \(6^2\):

\[
6^2 = 36
\]

Therefore:

\[
6^{-2} = \frac{1}{36}
\]

### Final Answer:
\[
6^{-2} = \frac{1}{36}
\]

Would you like further details or have any questions?

### Related Questions:
1. What is \(5^{-3}\)?
2. How do you simplify \(8^{-2}\)?
3. What is the value of \(7^{-1}\)?
4. How does \(3^{-4}\) compare to \(4^{-3}\)?
5. Can you explain how to simplify \(\left(\frac{2}{3}\right)^{-2}\)?

### Tip:
Remember, a negative exponent indicates the reciprocal of the base raised to the positive exponent!

Learn how to evaluate 6 raised to the power of -2 step-by-step with detailed explanations and examples. This problem involves applying the concept of negative exponents, specifically the formula a^{-n} = \frac{1}{a^n}. Suitable for students in Grades 6-8.

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