To evaluate $6^{-2}$, we need to apply the property of negative exponents, which states:

$a^{-n} = \frac{1}{a^n}$

So, for $6^{-2}$:

$6^{-2} = \frac{1}{6^2}$

Next, we calculate $6^2$:

$6^2 = 36$

Therefore:

$6^{-2} = \frac{1}{36}$

Final Answer:

$6^{-2} = \frac{1}{36}$

Would you like further details or have any questions?

Related Questions:

1. What is $5^{-3}$?
2. How do you simplify $8^{-2}$?
3. What is the value of $7^{-1}$?
4. How does $3^{-4}$ compare to $4^{-3}$?
5. Can you explain how to simplify $\left(\frac{2}{3}\right)^{-2}$?

Tip:

Remember, a negative exponent indicates the reciprocal of the base raised to the positive exponent!