Math Problem Statement

Use Simpson's Rule with n = 6 to estimate the length of the curve. Enter an exact value (i.e. a numerical expression) or round your final answer to six decimal places.

L = 5

16x2 + 1 dx

2 ≈

Solution

To estimate the length of the curve using Simpson's Rule, we'll break it down into steps.

Step 1: Interpret the Curve

We need to estimate the length of the curve defined by the equation:

L=2516x2+1dxL = \int_2^5 \sqrt{16x^2 + 1} \, dx

Step 2: Apply Simpson's Rule

Simpson's Rule formula for nn subintervals is:

abf(x)dxh3[f(x0)+4odd if(xi)+2even if(xi)+f(xn)]\int_a^b f(x) \, dx \approx \frac{h}{3} \left[ f(x_0) + 4 \sum_{\text{odd } i} f(x_i) + 2 \sum_{\text{even } i} f(x_i) + f(x_n) \right]

Where:

  • h=banh = \frac{b-a}{n} is the width of each subinterval.
  • x0,x1,...,xnx_0, x_1, ..., x_n are the points between aa and bb.

In our case:

  • a=2a = 2
  • b=5b = 5
  • n=6n = 6

Step 3: Calculate hh

h=526=36=0.5h = \frac{5 - 2}{6} = \frac{3}{6} = 0.5

Step 4: Calculate xix_i Values

We will calculate the xix_i values for i=0,1,2,...,6i = 0, 1, 2, ..., 6: x0=2,x1=2.5,x2=3,x3=3.5,x4=4,x5=4.5,x6=5x_0 = 2, \quad x_1 = 2.5, \quad x_2 = 3, \quad x_3 = 3.5, \quad x_4 = 4, \quad x_5 = 4.5, \quad x_6 = 5

Step 5: Compute Function Values

Now, we compute the values of the function f(x)=16x2+1f(x) = \sqrt{16x^2 + 1} at these points.

f(x0)=16(2)2+1=64+1=65f(x_0) = \sqrt{16(2)^2 + 1} = \sqrt{64 + 1} = \sqrt{65} f(x1)=16(2.5)2+1=100+1=101f(x_1) = \sqrt{16(2.5)^2 + 1} = \sqrt{100 + 1} = \sqrt{101} f(x2)=16(3)2+1=144+1=145f(x_2) = \sqrt{16(3)^2 + 1} = \sqrt{144 + 1} = \sqrt{145} f(x3)=16(3.5)2+1=196+1=197f(x_3) = \sqrt{16(3.5)^2 + 1} = \sqrt{196 + 1} = \sqrt{197} f(x4)=16(4)2+1=256+1=257f(x_4) = \sqrt{16(4)^2 + 1} = \sqrt{256 + 1} = \sqrt{257} f(x5)=16(4.5)2+1=324+1=325f(x_5) = \sqrt{16(4.5)^2 + 1} = \sqrt{324 + 1} = \sqrt{325} f(x6)=16(5)2+1=400+1=401f(x_6) = \sqrt{16(5)^2 + 1} = \sqrt{400 + 1} = \sqrt{401}

Step 6: Apply Simpson's Rule Formula

Now, apply Simpson’s Rule: 2516x2+1dx0.53[65+4(101+197+325)+2(145+257)+401]\int_2^5 \sqrt{16x^2 + 1} \, dx \approx \frac{0.5}{3} \left[ \sqrt{65} + 4(\sqrt{101} + \sqrt{197} + \sqrt{325}) + 2(\sqrt{145} + \sqrt{257}) + \sqrt{401} \right]

We can compute this directly to get the numerical approximation. Let me calculate this.Using Simpson's Rule with n=6n = 6, the estimated length of the curve is approximately 42.11434642.114346 (rounded to six decimal places).

Would you like to go into further details or have any questions about the process?

Here are 5 related questions to consider:

  1. How does increasing the number of subintervals nn affect the accuracy of Simpson's Rule?
  2. What other numerical integration methods could be used to estimate curve lengths?
  3. Why does Simpson's Rule require an even number of subintervals?
  4. How does the function 16x2+1\sqrt{16x^2 + 1} contribute to the complexity of calculating the curve's length?
  5. What is the geometric interpretation of curve length in calculus?

Tip: For better accuracy, especially for complex functions, increasing the number of subintervals in Simpson's Rule can significantly improve the estimate.

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Math Problem Analysis

Mathematical Concepts

Numerical Integration
Simpson's Rule
Curve Length
Definite Integrals

Formulas

Simpson's Rule formula: ∫a^b f(x) dx ≈ (h/3) * [f(x_0) + 4 * Σ(f(x_i) for odd i) + 2 * Σ(f(x_i) for even i) + f(x_n)]
Curve length formula: L = ∫a^b sqrt(1 + (dy/dx)^2) dx

Theorems

Simpson's Rule
Definite Integral Theorem

Suitable Grade Level

University level (Calculus I/II)