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The problem asks to write an equation in standard form for the line passing through the points \((-7, -8)\) and \((-7, 4)\).

### Step 1: Check if it's a vertical line
Notice that both points have the same \(x\)-coordinate, \(-7\). This means the line is vertical. For a vertical line, the equation is simply \(x = \text{constant}\), where the constant is the common \(x\)-coordinate.

### Step 2: Write the equation
Since both points have \(x = -7\), the equation of the line is:

\[
x = -7
\]

### Standard Form
In general, the standard form of a line is \(Ax + By = C\). For a vertical line like this, the equation \(x = -7\) can be written as:

\[
1x + 0y = -7
\]

or simply:

\[
x = -7
\]

This is the equation of the line in standard form.

Would you like further clarification or have additional questions?

Here are some related questions:
1. How would you write the equation of a horizontal line passing through two points?
2. What is the slope of a vertical line?
3. How does the equation of a line change if it is not vertical or horizontal?
4. Can you convert this vertical line equation into slope-intercept form?
5. How do you find the slope of a line between two non-vertical points?

**Tip:** For any vertical line, the slope is undefined, and the equation is always of the form \(x = \text{constant}\).

Write an equation in standard form for the line that passes through the given points (-7, -8) and (-7, 4).

Learn how to write the equation of a vertical line that passes through the points (-7, -8) and (-7, 4). This algebra problem helps understand the concept of vertical lines where x is constant. Suitable for students in Grades 8-10.

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