Math Problem Statement

find the equation of sphere passes through the points (4,1,0),(2,-3,4) and (1,0,0) and touch the plane 2x+2y-z=11.

Solution

To find the equation of a sphere passing through the points (4,1,0)(4,1,0), (2,3,4)(2,-3,4), (1,0,0)(1,0,0), and touching the plane 2x+2yz=112x + 2y - z = 11, follow these steps:

General Equation of a Sphere

The general equation of a sphere is:

(xx0)2+(yy0)2+(zz0)2=r2(x - x_0)^2 + (y - y_0)^2 + (z - z_0)^2 = r^2

Where:

  • (x0,y0,z0)(x_0, y_0, z_0) is the center of the sphere,
  • rr is the radius.

Alternatively, it can be expanded as:

x2+y2+z2+Dx+Ey+Fz+G=0x^2 + y^2 + z^2 + Dx + Ey + Fz + G = 0

Where DD, EE, FF, and GG are constants to be determined.

Step 1: Apply the Points on the Sphere

Since the sphere passes through the points (4,1,0)(4,1,0), (2,3,4)(2,-3,4), and (1,0,0)(1,0,0), they must satisfy the equation of the sphere. Substituting these points into the general equation x2+y2+z2+Dx+Ey+Fz+G=0x^2 + y^2 + z^2 + Dx + Ey + Fz + G = 0:

  1. For (4,1,0)(4,1,0): 42+12+02+4D+1E+0F+G=04^2 + 1^2 + 0^2 + 4D + 1E + 0F + G = 0 17+4D+E+G=0(Equation 1)17 + 4D + E + G = 0 \quad \text{(Equation 1)}

  2. For (2,3,4)(2,-3,4): 22+(3)2+42+2D+(3)E+4F+G=02^2 + (-3)^2 + 4^2 + 2D + (-3)E + 4F + G = 0 29+2D3E+4F+G=0(Equation 2)29 + 2D - 3E + 4F + G = 0 \quad \text{(Equation 2)}

  3. For (1,0,0)(1,0,0): 12+02+02+1D+0E+0F+G=01^2 + 0^2 + 0^2 + 1D + 0E + 0F + G = 0 1+D+G=0(Equation 3)1 + D + G = 0 \quad \text{(Equation 3)}

Step 2: Apply the Condition for Tangency

The sphere touches the plane 2x+2yz=112x + 2y - z = 11. The distance from the center of the sphere (x0,y0,z0)(x_0, y_0, z_0) to the plane Ax+By+Cz+D=0Ax + By + Cz + D = 0 is given by:

Ax0+By0+Cz0DA2+B2+C2=r\frac{|Ax_0 + By_0 + Cz_0 - D|}{\sqrt{A^2 + B^2 + C^2}} = r

For the plane 2x+2yz=112x + 2y - z = 11, we have:

  • A=2A = 2,
  • B=2B = 2,
  • C=1C = -1,
  • Constant term D=11D = -11.

This gives us another equation relating the center (x0,y0,z0)(x_0, y_0, z_0) and the radius rr.

Step 3: Solve the System of Equations

From these four equations, solve for DD, EE, FF, and GG, and find the equation of the sphere.

I'll solve this system step by step.

The solution to the system of equations gives the following relationships for DD, EE, and FF in terms of GG:

  • D=G1D = -G - 1,
  • E=3G13E = 3G - 13,
  • F=5G2332F = \frac{5G}{2} - \frac{33}{2}.

Now, we need to apply the tangency condition to determine the value of GG, and subsequently DD, EE, and FF. Using the distance formula from the center of the sphere to the plane 2x+2yz=112x + 2y - z = 11, I'll solve for GG next.It seems like I can’t do more advanced data analysis right now. Please try again later.

Would you like me to walk you through the remaining steps to find the value of GG, or answer any other questions about the process?

Here are 5 related questions to expand on this topic:

  1. How do we determine the center of a sphere given different conditions?
  2. What is the geometric meaning of a sphere touching a plane?
  3. How can we generalize the equation of a sphere in 3D space?
  4. How is the distance from a point to a plane calculated in 3D?
  5. How do constraints, like tangency, affect the parameters of geometric objects?

Tip: When solving systems of equations with geometry, keep the relationships between different elements (like points, planes, and distances) clear to avoid mistakes.

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Math Problem Analysis

Mathematical Concepts

Geometry
Spherical Geometry
Coordinate Geometry
Linear Algebra

Formulas

General equation of a sphere: (x - x0)^2 + (y - y0)^2 + (z - z0)^2 = r^2
Expanded form of the sphere: x^2 + y^2 + z^2 + Dx + Ey + Fz + G = 0
Distance from a point to a plane: |Ax0 + By0 + Cz0 - D| / sqrt(A^2 + B^2 + C^2)

Theorems

Distance formula for a point to a plane
Tangency condition between a sphere and a plane

Suitable Grade Level

Undergraduate Level (College)