line that passes through the points left parenthesis, minus, 6, comma, minus, 4, right parenthesis(−6,−4) and left parenthesis, minus, 5, comma, minus, 4, right parenthesis(−5,−4)

To find the equation of the line that passes through the points \((-6, -4)\) and \((-5, -4)\), let's start by calculating the slope \(m\) using the formula:

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Given the points \((-6, -4)\) and \((-5, -4)\), we can label the coordinates as:
\[
(x_1, y_1) = (-6, -4) \quad \text{and} \quad (x_2, y_2) = (-5, -4)
\]

Now, substitute these values into the slope formula:

\[
m = \frac{-4 - (-4)}{-5 - (-6)} = \frac{0}{1} = 0
\]

Since the slope \(m = 0\), this indicates that the line is horizontal. A horizontal line has the form \(y = c\), where \(c\) is the constant \(y\)-coordinate of the points on the line.

Both points have \(y = -4\), so the equation of the line is:

\[
y = -4
\]

### Conclusion:
The equation of the line passing through \((-6, -4)\) and \((-5, -4)\) is:
\[
y = -4
\]

Would you like more details or have any questions?

Here are 5 related questions:
1. How do you find the equation of a vertical line?
2. What does the slope of a line tell you about its direction?
3. Can a line have an undefined slope, and what would that mean?
4. How do you convert a linear equation into slope-intercept form?
5. What is the general formula for a line passing through two points?

**Tip:** A line with a slope of zero is always horizontal and its equation is always of the form \(y = \text{constant}\).

line that passes through the points (−6,−4) and (−5,−4)

Learn how to find the equation of a line passing through the points (−6,−4) and (−5,−4). This problem covers key concepts in coordinate geometry, such as calculating the slope and determining the equation of a horizontal line. Suitable for students in Grades 6-8.

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