The image contains a problem asking to find the equation of a line parallel to the line $y = -3x + 2$ and passing through the point $(-8, -1)$.

To solve this:

1. Identify the slope of the given line $y = -3x + 2$, which is the coefficient of $x$. This is $m = -3$.

2. Use the point-slope form of the equation of a line, which is:

$y - y_1 = m(x - x_1)$

Where $m$ is the slope and $(x_1, y_1)$ is the point through which the line passes. Here, the point is $(-8, -1)$ and the slope is $m = -3$.

3. Substitute the values into the point-slope form:

$y - (-1) = -3(x - (-8))$

Simplifying:

$y + 1 = -3(x + 8)$

4. Distribute the slope:

$y + 1 = -3x - 24$

5. Solve for $y$ by subtracting 1 from both sides:

$y = -3x - 25$

Thus, the equation of the line parallel to $y = -3x + 2$ passing through $(-8, -1)$ is:

$y = -3x - 25$

Would you like further clarification or have any additional questions on this problem? Here are some related questions you can explore:

1. How do you find the slope of a line from its equation?
2. What is the point-slope form of the equation of a line?
3. How do you convert from point-slope form to slope-intercept form?
4. How do parallel lines relate to their slopes?
5. How do you find the equation of a line passing through a point with a given slope?

Tip: When writing the equation of a line, always check that you use the correct form depending on the information given (e.g., point-slope, slope-intercept).