Math Problem Statement
Use epsilon delta theory for limit to prove that lim x->0 (x*cos(1/x))=0
Solution
To prove using the ε-δ (epsilon-delta) definition of a limit that:
we must demonstrate that for every ε > 0, there exists a corresponding δ > 0 such that whenever , the following inequality holds:
Step-by-step proof:
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Starting with the absolute value of the function:
We want to prove that:
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Bound the cosine function:
Since is bounded for all (because cosine always satisfies for any real ), we have:
This implies:
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Simplifying the expression:
Using the bound , we get:
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Applying the ε-δ definition:
Now we need to make sure that for any ε > 0, we can find a δ > 0 such that:
This choice of δ is straightforward: we can simply choose . Therefore, if , we have:
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Conclusion:
Thus, by choosing , we satisfy the condition required by the ε-δ definition. Therefore, we have proven that:
This completes the proof using the epsilon-delta definition of a limit.
Would you like to go deeper into any part of the explanation or have any questions?
Here are some related questions:
- How does the bounded nature of cosine help in epsilon-delta proofs?
- Can we generalize this technique for other oscillatory functions?
- How do we choose δ in more complex limits?
- What happens if the cosine function was unbounded near 0?
- Why is epsilon-delta definition crucial in proving limits formally?
Tip: When dealing with oscillating functions like , bounding them is a useful strategy in epsilon-delta proofs.
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Math Problem Analysis
Mathematical Concepts
Limits
Epsilon-Delta Definition
Oscillatory Functions
Formulas
|x cos(1/x)| < ε
-1 ≤ cos(θ) ≤ 1
Theorems
Epsilon-Delta Definition of a Limit
Suitable Grade Level
Undergraduate Level (Calculus I or II)
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