Math Problem Statement

Use epsilon delta theory for limit to prove that lim x->0 (x*cos(1/x))=0

Solution

To prove using the ε-δ (epsilon-delta) definition of a limit that:

limx0xcos(1x)=0,\lim_{x \to 0} x \cos \left( \frac{1}{x} \right) = 0,

we must demonstrate that for every ε > 0, there exists a corresponding δ > 0 such that whenever 0<x<δ0 < |x| < \delta, the following inequality holds:

xcos(1x)0=xcos(1x)<ϵ.\left| x \cos \left( \frac{1}{x} \right) - 0 \right| = \left| x \cos \left( \frac{1}{x} \right) \right| < \epsilon.

Step-by-step proof:

  1. Starting with the absolute value of the function:

    We want to prove that: xcos(1x)<ϵ.\left| x \cos \left( \frac{1}{x} \right) \right| < \epsilon.

  2. Bound the cosine function:

    Since cos(1x)\cos \left( \frac{1}{x} \right) is bounded for all x0x \neq 0 (because cosine always satisfies 1cos(θ)1-1 \leq \cos(\theta) \leq 1 for any real θ\theta), we have: 1cos(1x)1.-1 \leq \cos \left( \frac{1}{x} \right) \leq 1.

    This implies: cos(1x)1.\left| \cos \left( \frac{1}{x} \right) \right| \leq 1.

  3. Simplifying the expression:

    Using the bound cos(1x)1\left| \cos \left( \frac{1}{x} \right) \right| \leq 1, we get: xcos(1x)x.\left| x \cos \left( \frac{1}{x} \right) \right| \leq |x|.

  4. Applying the ε-δ definition:

    Now we need to make sure that for any ε > 0, we can find a δ > 0 such that: x<δ    x<ϵ.|x| < \delta \implies |x| < \epsilon.

    This choice of δ is straightforward: we can simply choose δ=ϵ\delta = \epsilon. Therefore, if x<δ|x| < \delta, we have: xcos(1x)x<ϵ.|x \cos \left( \frac{1}{x} \right)| \leq |x| < \epsilon.

  5. Conclusion:

    Thus, by choosing δ=ϵ\delta = \epsilon, we satisfy the condition required by the ε-δ definition. Therefore, we have proven that: limx0xcos(1x)=0.\lim_{x \to 0} x \cos \left( \frac{1}{x} \right) = 0.

This completes the proof using the epsilon-delta definition of a limit.


Would you like to go deeper into any part of the explanation or have any questions?

Here are some related questions:

  1. How does the bounded nature of cosine help in epsilon-delta proofs?
  2. Can we generalize this technique for other oscillatory functions?
  3. How do we choose δ in more complex limits?
  4. What happens if the cosine function was unbounded near 0?
  5. Why is epsilon-delta definition crucial in proving limits formally?

Tip: When dealing with oscillating functions like cos(1/x)\cos(1/x), bounding them is a useful strategy in epsilon-delta proofs.

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Math Problem Analysis

Mathematical Concepts

Limits
Epsilon-Delta Definition
Oscillatory Functions

Formulas

|x cos(1/x)| < ε
-1 ≤ cos(θ) ≤ 1

Theorems

Epsilon-Delta Definition of a Limit

Suitable Grade Level

Undergraduate Level (Calculus I or II)