To solve this problem, we need to calculate the energy stored in each capacitor when a potential difference of 100 V is applied across points A and B.

Step 1: Analyzing the Circuit

1. Identify Capacitor Arrangement: The capacitors $C_1 = 1.5 \ \mu\text{F}$, $C_2 = 0.75 \ \mu\text{F}$, and $C_3 = 0.5 \ \mu\text{F}$ are connected in a mixed series-parallel arrangement.
   • $C_1$ and $C_2$ are in series.
   • The combined series result of $C_1$ and $C_2$ is in parallel with $C_3$.

Step 2: Equivalent Capacitance

1. Calculate Equivalent Capacitance of $C_1$ and $C_2$: $\frac{1}{C_{12}} = \frac{1}{C_1} + \frac{1}{C_2}$ Plugging in the values: [ \frac{1}{C_{12}} = \frac{1}{1.5 \ \mu\text{F}} + \frac{1}{0.75 \ \mu\text{F}} = \frac{1}{1.5} + \frac{1}{0.75} = \frac{2}{1.5} = \frac{2}{1.5} + \frac{4}{