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To solve this problem, we need to calculate the energy stored in each capacitor when a potential difference of 100 V is applied across points A and B.

### Step 1: Analyzing the Circuit
1. **Identify Capacitor Arrangement**: 
   The capacitors \( C_1 = 1.5 \ \mu\text{F} \), \( C_2 = 0.75 \ \mu\text{F} \), and \( C_3 = 0.5 \ \mu\text{F} \) are connected in a mixed series-parallel arrangement.
   - \( C_1 \) and \( C_2 \) are in series.
   - The combined series result of \( C_1 \) and \( C_2 \) is in parallel with \( C_3 \).

### Step 2: Equivalent Capacitance
1. **Calculate Equivalent Capacitance of \( C_1 \) and \( C_2 \)**:
   \[
   \frac{1}{C_{12}} = \frac{1}{C_1} + \frac{1}{C_2}
   \]
   Plugging in the values:
   \[
   \frac{1}{C_{12}} = \frac{1}{1.5 \ \mu\text{F}} + \frac{1}{0.75 \ \mu\text{F}} = \frac{1}{1.5} + \frac{1}{0.75} = \frac{2}{1.5} = \frac{2}{1.5} + \frac{4}{

Tenemos los tres condensadores de la figura, donde C1 = 1.5 μF, C2 = 0.75 μF, y C3 = 0.5 μF; si se aplica entre los bornes A y B una diferencia de potencial de 100 V ¿Cuál es la energía almacenada en cada uno?

Solve for the energy stored in each capacitor (C1 = 1.5 μF, C2 = 0.75 μF, C3 = 0.5 μF) in a mixed series-parallel arrangement with a 100V potential. Includes step-by-step calculations using series and parallel capacitance formulas and the energy formula.

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