The problem provided involves calculating the electrostatic force between two charged particles. To do this, we'll use Coulomb's Law, which is defined by the formula:

$F = k \cdot \frac{|q_1 \cdot q_2|}{r^2}$

Where:

• $F$ is the electrostatic force between the particles.
• $k$ is the electrostatic constant ($9.0 \times 10^9 \, \text{N·m}^2/\text{C}^2$).
• $q_1$ and $q_2$ are the charges of the particles.
• $r$ is the distance between the particles (in meters).

Given:

• $q_1 = 5.0 \times 10^{-4} \, \text{C}$
• $q_2 = 10.0 \times 10^{-9} \, \text{C}$
• $r = 2.0 \, \text{cm} = 0.02 \, \text{m}$

Now, I will compute the electrostatic force.

Let me calculate it.The electrostatic force between the two particles is approximately $112.5 \, \text{N}$.

Would you like further clarification or additional details on this problem? Here are some related questions that could help expand your understanding:

1. What happens to the force if the distance between the particles is doubled?
2. How does the force change if one of the charges is doubled?
3. What is the direction of the force between the two particles?
4. How would the result change if the medium between the particles were different (e.g., water instead of air)?
5. Can you describe an example of when this force might be significant in real-world scenarios?

Tip: Remember that the electrostatic force is inversely proportional to the square of the distance between charges, so small changes in distance can lead to large changes in force magnitude.