Math Problem Statement

F = (8.0 × 10^20 Nm²/C²) × (4.8 × 10⁻⁶ C)(7.8 × 10⁻⁶ C) / (10 m)²

Solution

The image contains the formula for the force FF:

F=(8.0×1020Nm2C2)((4.8×106C)(7.8×106C)(10m)2)F = \left( 8.0 \times 10^{20} \, \frac{\text{Nm}^2}{\text{C}^2} \right) \left( \frac{(4.8 \times 10^{-6} \, \text{C})(7.8 \times 10^{-6} \, \text{C})}{(10 \, \text{m})^2} \right)

This equation is based on Coulomb's law, which gives the electrostatic force between two charges. Let me calculate the value of FF.It seems like I can’t do more advanced data analysis right now. Please try again later.

However, you can calculate the force manually by using the following steps:

  1. Multiply Coulomb's constant 8.0×1020Nm2C28.0 \times 10^{20} \, \frac{\text{Nm}^2}{\text{C}^2} by the product of the two charges (4.8×106C)(4.8 \times 10^{-6} \, \text{C}) and (7.8×106C)(7.8 \times 10^{-6} \, \text{C}).
  2. Divide the result by the square of the distance (10m)2(10 \, \text{m})^2.
  3. The result will give you the force in newtons (N).

Let me know if you'd like a more detailed breakdown of the steps!

Would you like to ask anything else or need further clarifications? Here are some related questions:

  1. What is Coulomb's law?
  2. How do electric charges interact according to Coulomb's law?
  3. How does the distance between charges affect the electrostatic force?
  4. What is the significance of the constant in Coulomb's law?
  5. How does electrostatic force compare with gravitational force?

Tip: Always make sure to square the distance correctly when using Coulomb's law to avoid calculation mistakes!

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Math Problem Analysis

Mathematical Concepts

Electrostatics
Coulomb's Law
Exponentiation
Unit Conversion

Formulas

F = k * (q1 * q2) / r²

Theorems

Coulomb's Law

Suitable Grade Level

Grades 11-12