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The question you're asking about concerns electrostatic force and how it changes when the charges on two objects double. This scenario is governed by **Coulomb's Law**, which states that the electrostatic force \( F \) between two charges \( q_1 \) and \( q_2 \) is proportional to the product of the charges and inversely proportional to the square of the distance between them:

\[
F = k \cdot \frac{q_1 \cdot q_2}{r^2}
\]

Where:
- \( F \) is the electrostatic force,
- \( k \) is Coulomb's constant,
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and
- \( r \) is the distance between the charges.

Now, if the charge on both objects doubles (i.e., \( q_1 \) and \( q_2 \) both become \( 2q_1 \) and \( 2q_2 \)), the new force \( F' \) is:

\[
F' = k \cdot \frac{(2q_1) \cdot (2q_2)}{r^2} = k \cdot \frac{4 \cdot q_1 \cdot q_2}{r^2} = 4 \cdot F
\]

So, the force becomes **four times** (quadrupled) the original force.

Thus, the correct answer is **"The force is quadrupled."**

Do you need more details or have any other questions?

### 5 Related Questions:
1. What happens to the electrostatic force if the distance between the charges is halved?
2. How does Coulomb's Law compare to gravitational force in terms of the inverse-square law?
3. What would happen if only one charge is doubled while the other stays the same?
4. What is Coulomb’s constant and how is it derived?
5. How would the force change if the charges were tripled instead of doubled?

**Tip:** Always remember that the electrostatic force depends on both the magnitude of the charges and the distance between them.

Two objects with equal charges are placed at a certain distance apart. If the charge on both objects doubles, how does the electrostatic force between them change?

This problem explains how the electrostatic force between two objects changes when their charges double. Based on Coulomb's Law, the force is quadrupled when the charges double. Suitable for high school students studying electrostatics and physics.

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