The electric flux $\Phi_E$ through a closed surface is related to the enclosed charge $Q_{\text{enc}}$ by Gauss's Law, which is given by the equation:

$\Phi_E = \frac{Q_{\text{enc}}}{\epsilon_0}$

Where:

• $\Phi_E$ is the electric flux,
• $Q_{\text{enc}}$ is the enclosed charge,
• $\epsilon_0$ is the permittivity of free space, and its value is approximately $8.85 \times 10^{-12} \, \text{C}^2/\text{N·m}^2$.

Given that the enclosed charge $Q_{\text{enc}} = 1.5 \, \text{C}$, we can calculate the electric flux:

$\Phi_E = \frac{1.5}{8.85 \times 10^{-12}}$

Let's calculate this value.

$\Phi_E = 1.695 \times 10^{11} \, \text{N·m}^2/\text{C}$

So, the electric flux is approximately $1.7 \times 10^{11} \, \text{N·m}^2/\text{C}$.

Would you like further clarification on this calculation or related topics?

Further questions:

1. What is the significance of the permittivity of free space in Gauss's Law?
2. How does the electric flux change with the size of the enclosing surface?
3. What happens to the electric flux if the charge is placed outside the surface?
4. How do you apply Gauss's Law to spherical or cylindrical symmetry?
5. What other equations are derived from Gauss’s Law in electrostatics?

Tip: When using Gauss's Law, make sure the symmetry of the charge distribution matches the symmetry of the surface for easier calculation of flux.