Math Problem Statement

il modulo del campo ele 4 Un filo metallico lungo e sottile ha una densità lineare di carica X = 3,2 x 10° C/m. A quale distanza dal filo occorre porre una carica negativa puntiforme di modulo 1,0 10° C, affinché essa sia attratta dal filo con una forza elettrica di 1,0 x 10 N?

5 Una superficie gaussiana sferica di raggio 2,5 m circonda un insieme di cariche situate al centro della stera. Determina it flusso del campo elettrico attraverso la superficie se la carica totale è 3,2 µC. Come

cambierebbe il flusso se le cariche fossero situate a 1,0 m dal centro della sfera?

6 Due lastre piane parallele infinite hanno ciascuna densità superficiale di carica pari a 6,4 × 10° C/m².

di entrambe sia positiva, negativa o una sia positiva e l'altra negativa. b) Determina il valore del campo elettrico nei tre casi.

a) Rappresenta le linee del campo elettrico all'interno e all'esterno delle due lastre, nel caso in cui la carica

VERIFICA CAMPO ELETTRICO - various questions related to electric field, including calculation of electric field due to charges, Gauss's Law, and electric field between parallel plates.

Solution

This document appears to be a physics test or worksheet on electric fields and charges. Here is an overview and potential answers to the questions based on the content visible in the image:

  1. Electric Field Due to a Point Charge
    The first problem likely involves calculating the electric field generated by a single point charge QQ at a distance rr. The formula for the electric field EE due to a point charge is: E=kQr2E = \frac{k \cdot |Q|}{r^2} where kk is Coulomb's constant, approximately 8.99×109N m2/C28.99 \times 10^9 \, \text{N m}^2/\text{C}^2.

  2. Proportionality of Electric Field
    This question could be testing the concept that the electric field from a point charge diminishes with the square of the distance from the charge (inverse-square law).

  3. Electric Field Between Charges
    This problem involves three charges placed at the vertices of a square, requiring calculation of the resulting electric field at the center of the square. The solution likely involves using vector addition of fields created by each charge.

  4. Force Due to a Charged Wire
    The problem describes a long, thin wire with a linear charge density of λ=3.2×106C/m\lambda = 3.2 \times 10^{-6} \, \text{C/m} and asks for the distance rr where a point charge experiences a specific force. The electric field near a line of charge can be found using: E=λ2πϵ0rE = \frac{\lambda}{2 \pi \epsilon_0 r} Using F=qEF = qE, you can solve for rr.

  5. Electric Flux Through a Spherical Gaussian Surface
    For this question, Gauss's Law can be applied: Φ=Qencϵ0\Phi = \frac{Q_{\text{enc}}}{\epsilon_0} where QencQ_{\text{enc}} is the enclosed charge. This problem requires calculating flux for a spherical Gaussian surface around a charge of 3.2μC3.2 \, \mu \text{C}.

  6. Electric Field Between Infinite Parallel Plates
    Here, two infinite plates with surface charge density σ=6.4×106C/m2\sigma = 6.4 \times 10^{-6} \, \text{C/m}^2 are given. The problem may require drawing field lines for different configurations and calculating the electric field using: E=σ2ϵ0E = \frac{\sigma}{2 \epsilon_0} if both are positive or both are negative, and double this value if they are oppositely charged.

Would you like a detailed solution for any specific question, or have any particular question about the setup?


Related Questions

  1. How does the distance between charges affect the magnitude of the electric field in a system of charges?
  2. What is the importance of Gauss's Law when dealing with symmetric charge distributions?
  3. Why does the electric field outside a long, charged wire decay with distance differently than that of a point charge?
  4. How would the electric flux change if the Gaussian surface were changed from spherical to cylindrical?
  5. What impact does the orientation of parallel plates have on the resulting electric field configuration?

Tip

When calculating electric fields in symmetric charge distributions, always check if Gauss's Law can simplify the process by using symmetry to avoid complex integration.

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Math Problem Analysis

Mathematical Concepts

Electric Field
Coulomb's Law
Gauss's Law
Electric Flux
Electric Field of Parallel Plates

Formulas

Electric field of point charge: E = k * |Q| / r^2
Electric field near a line of charge: E = λ / (2 * π * ε₀ * r)
Gauss's Law: Φ = Q_enc / ε₀
Electric field between parallel plates: E = σ / ε₀

Theorems

Gauss's Law

Suitable Grade Level

Grades 11-12