Math Problem Statement

A square insulating sheet whose sides have length L is held horizontally. The sheet has a charge of Q spread uniformly over its area. Calculate the electric field at a point located a distance r1 above the center of the sheet. Use the appropriate approximations based on the fact that
r1 ≪ L

Solution

To calculate the electric field at a point located a distance r1r_1 above the center of a square insulating sheet with uniformly distributed charge, we can use the approximation that r1Lr_1 \ll L, where LL is the side length of the square.

Problem Breakdown:

  • The sheet has a uniform charge distribution of QQ spread over an area of side length LL.
  • We are interested in the electric field at a point located a distance r1r_1 above the center of the sheet.
  • The condition r1Lr_1 \ll L suggests that the point is very close to the sheet compared to its size, which allows us to treat the system as if it were an infinite plane of charge.

Step 1: Charge Distribution

The surface charge density σ\sigma (charge per unit area) of the sheet is given by: σ=QL2\sigma = \frac{Q}{L^2} where L2L^2 is the area of the square sheet.

Step 2: Electric Field of an Infinite Sheet of Charge

For an infinite sheet of charge with uniform surface charge density σ\sigma, the electric field at a point near the sheet is given by: E=σ2ϵ0E = \frac{\sigma}{2\epsilon_0} where:

  • ϵ0\epsilon_0 is the permittivity of free space.
  • σ\sigma is the surface charge density.

This electric field points perpendicular to the surface of the sheet and has the same magnitude on both sides of the sheet. The factor of 12\frac{1}{2} comes from the fact that the electric field from an infinite sheet is the result of contributions from all points on the sheet.

Step 3: Applying the Approximation

Since r1Lr_1 \ll L, we can approximate the square sheet as an infinite sheet of charge. Thus, the electric field at a point a distance r1r_1 above the center of the sheet is approximately: Eσ2ϵ0E \approx \frac{\sigma}{2\epsilon_0}

Step 4: Final Expression for the Electric Field

Substitute the expression for σ\sigma into the equation: EQ2ϵ0L2E \approx \frac{Q}{2\epsilon_0 L^2}

Thus, the electric field at a distance r1r_1 above the center of the sheet is: EQ2ϵ0L2E \approx \frac{Q}{2\epsilon_0 L^2}

Conclusion:

This is the magnitude of the electric field for the given conditions r1Lr_1 \ll L, and it is directed perpendicular to the surface of the sheet (either upward or downward depending on the charge distribution).


Do you need more details about this calculation or have any other questions? Here are some related topics you might find useful:

  1. How does the electric field vary with distance for different charge distributions (point charge, dipole, infinite plane)?
  2. Derivation of the electric field for an infinite plane of charge.
  3. Electric potential due to a uniformly charged square sheet.
  4. Electric field due to a circular sheet of charge.
  5. How does the electric field change if the observation point is farther from the sheet (when r1r_1 is comparable to LL)?

Tip: The electric field near a uniformly charged sheet can often be approximated as that of an infinite sheet, simplifying the problem greatly.

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Math Problem Analysis

Mathematical Concepts

Electric Field
Charge Distribution
Surface Charge Density
Approximation of Infinite Sheet of Charge

Formulas

Electric Field due to Infinite Sheet: E = σ / (2ε₀)
Surface Charge Density: σ = Q / L²
Final Electric Field: E ≈ Q / (2ε₀ L²)

Theorems

Gauss's Law for Electric Fields
Approximation of Electric Field for Infinite Plane of Charge

Suitable Grade Level

Grades 11-12