https://file.aiquickdraw.com/mathbot/file/172951913263119j961u0.jpg

The problem in the image involves two objects with the same mass \( m_1 = m_2 = 2 \, \text{kg} \), moving towards each other. The velocities before the collision are \( v_1 = 10 \, \text{m/s} \) and \( v_2 = 20 \, \text{m/s} \), and the collision is described as a perfectly elastic collision ("tumbukan lenting sempurna").

### Key points for solving:
1. **Conservation of Momentum**: In any collision, momentum is conserved. 
   \[
   m_1 v_1 + m_2 v_2 = m_1 v_1' + m_2 v_2'
   \]
   where \( v_1' \) and \( v_2' \) are the velocities after the collision.

2. **Conservation of Kinetic Energy**: For a perfectly elastic collision, kinetic energy is also conserved.
   \[
   \frac{1}{2} m_1 v_1^2 + \frac{1}{2} m_2 v_2^2 = \frac{1}{2} m_1 v_1'^2 + \frac{1}{2} m_2 v_2'^2
   \]

Since \( m_1 = m_2 \), and after simplifying the system of equations, we can use the following formula for a perfectly elastic collision between two objects of equal mass:
\[
v_1' = v_2
\]
\[
v_2' = v_1
\]

### Applying the Formula:
- Before the collision:
  \[
  v_1 = 10 \, \text{m/s}, \quad v_2 = 20 \, \text{m/s}
  \]
- After the collision (since \( m_1 = m_2 \)):
  \[
  v_1' = v_2 = 20 \, \text{m/s}, \quad v_2' = v_1 = 10 \, \text{m/s}
  \]

### Conclusion:
The correct answer is **option e**:  
\( v_1' = 5 \, \text{m/s} \quad v_2' = 10 \, \text{m/s} \).

Let me know if you'd like further clarification or have additional questions!

Dua benda m1 = m2 = 2 kg bergerak saling mendekati seperti gambar. v1 = 10 m/s dan v2 = 20 m/s. Jika kedua benda bertumbukan lenting sempurna, maka kecepatan masing-masing benda setelah bertumbukan adalah?

This physics problem involves a perfectly elastic collision between two objects with equal mass (m1 = m2 = 2 kg) moving towards each other. It covers the conservation of momentum and kinetic energy, using velocities of v1 = 10 m/s and v2 = 20 m/s to find post-collision speeds.

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