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The question asks what would happen if a coil made from thinner wire but with the same number of turns and coil diameter is used. Let's break it down:

- **Thinner wire**: This means the wire has a smaller cross-sectional area, which leads to an increase in resistance according to the formula \( R = \frac{\rho L}{A} \), where \( A \) is the cross-sectional area.
- **Same number of turns and diameter**: This keeps the coil geometry constant.

### Impact:
- **Increased resistance**: Thinner wire has higher resistance, reducing the current flowing through the coil for the same applied voltage (Ohm’s Law: \( V = IR \)).
- **Torque**: Torque in a coil (e.g., in motors) depends on the current and magnetic field. Since the current decreases due to higher resistance, the torque produced will also reduce.

### Correct answer:
- **Both B and C**: The torque produced will decrease, and the current flowing through the coil will also reduce.

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Here are 5 questions related to this concept:
1. How does the cross-sectional area of a wire affect its resistance?
2. What is the relationship between current and torque in a coil?
3. How does increasing the resistance affect the current in a circuit with constant voltage?
4. What other factors, aside from resistance, can influence torque in an electromagnetic coil?
5. How is power loss in a coil affected by the resistance of the wire?

**Tip**: In electromagnetism, the performance of a coil depends heavily on the wire's resistance, which influences the current flow and the resulting magnetic field.

A coil of same number of turns and coil diameter made from a thinner wire would: 
- Increase the torque produced 
- Reduce the torque produced 
- Reduce the current flowing through the coil 
- Both B and C

Explore how a coil with the same number of turns and diameter, but made from thinner wire, reduces both torque and current. This problem explains key physics concepts related to electromagnetism, resistance, and current flow in a coil. Ideal for high school physics students.

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