The task shown in the image involves finding and drawing the height of a triangle. Each triangle has a labeled base $b$, and the instruction is to draw a line segment representing the height. Here's how you can approach it:

1. Height in Triangles: The height (or altitude) of a triangle is the perpendicular distance from the base to the opposite vertex. It forms a right angle with the base.

2. First Triangle: The base $b$ is horizontal. The height would be a vertical line segment from the top vertex down to the base, forming a right angle with the base.

3. Second Triangle: This triangle is tilted, but the base is still labeled $b$. The height will be a perpendicular line from the top vertex (not on the base) down to the base.

4. Third Triangle: This triangle is more acute and also tilted. The height will again be a perpendicular line from the topmost vertex (above the base) down to the line segment forming the base.

You can use a straight edge or index card, as suggested, to ensure that the lines are perpendicular.

Would you like more details on how to draw the height for each triangle?

Here are some related questions:

1. How do you calculate the area of a triangle using its base and height?
2. How is the height different in an equilateral triangle compared to a right triangle?
3. What is the role of height in finding the centroid of a triangle?
4. How do you determine the height in an obtuse triangle where the height falls outside the triangle?
5. Can you always use any side of the triangle as the base?

Tip: The height in a triangle is always perpendicular to the base, even if it extends outside the triangle (for obtuse triangles).