The question on the screen asks about how the perimeter of a square changes when the side lengths are doubled.

Given:

• The original side length of the square is 8 mm.
• The perimeter $P$ of a square is given by $P = 4 \times \text{side length}$.

Step-by-step process:

1. Original Perimeter:

   • Side length = 8 mm.
   • Original Perimeter = $4 \times 8 = 32$ mm.

2. New Perimeter when Side Lengths are Doubled:

   • New side length = $2 \times 8 = 16$ mm.
   • New Perimeter = $4 \times 16 = 64$ mm.

Comparison:

The new perimeter (64 mm) is 2 times the original perimeter (32 mm).

Correct Answer:

• "The new perimeter will be 2 times the old perimeter."

Would you like more detailed explanations or have any other questions?

Here are some related questions for further exploration:

1. What happens to the area when the side lengths of a square are doubled?
2. If the side length is tripled, how does the perimeter change?
3. How does the perimeter of a rectangle change if only one side is doubled?
4. What is the general formula for the perimeter of polygons?
5. How do scale factors affect both perimeter and area?

Tip: Remember, perimeter increases linearly with side length changes, while area increases quadratically!