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The question on the screen asks about how the perimeter of a square changes when the side lengths are doubled.

### Given:
- The original side length of the square is 8 mm.
- The perimeter \( P \) of a square is given by \( P = 4 \times \text{side length} \).

### Step-by-step process:
1. **Original Perimeter:**
   - Side length = 8 mm.
   - Original Perimeter = \( 4 \times 8 = 32 \) mm.

2. **New Perimeter when Side Lengths are Doubled:**
   - New side length = \( 2 \times 8 = 16 \) mm.
   - New Perimeter = \( 4 \times 16 = 64 \) mm.

### Comparison:
The new perimeter (64 mm) is **2 times** the original perimeter (32 mm).

### Correct Answer:
- "The new perimeter will be 2 times the old perimeter."

Would you like more detailed explanations or have any other questions?

Here are some related questions for further exploration:
1. What happens to the area when the side lengths of a square are doubled?
2. If the side length is tripled, how does the perimeter change?
3. How does the perimeter of a rectangle change if only one side is doubled?
4. What is the general formula for the perimeter of polygons?
5. How do scale factors affect both perimeter and area?

**Tip:** Remember, perimeter increases linearly with side length changes, while area increases quadratically!

If the side lengths are doubled, which of the following statements about its perimeter will be true?

Explore how doubling the side lengths of a square affects its perimeter. Using basic geometry, learn how the perimeter scales linearly when the side length is doubled. This problem is suitable for students in Grades 5-7.

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