Math Problem Statement

Evaluate the double integral: ∫ from 1 to 2 ∫ from 4 to 6 (x/y^2) dy dx. Options: (a) 0.25 (b) 1.25 (c) 0.125 (d) 1

Solution

We are tasked with evaluating the double integral:

1246xy2dydx\int_1^2 \int_4^6 \frac{x}{y^2} \, dy \, dx

Let's proceed step-by-step:

Step 1: Solve the inner integral with respect to yy

The inner integral is:

46xy2dy\int_4^6 \frac{x}{y^2} \, dy

Since xx is treated as a constant with respect to yy, we can factor it out:

x461y2dyx \int_4^6 \frac{1}{y^2} \, dy

Now, solve 1y2dy\int \frac{1}{y^2} \, dy. The antiderivative of 1y2\frac{1}{y^2} is:

1y-\frac{1}{y}

So the inner integral becomes:

x[1y]46=x(16+14)x \left[ -\frac{1}{y} \right]_4^6 = x \left( -\frac{1}{6} + \frac{1}{4} \right)

Simplifying the expression inside the parentheses:

x(1416)=x(312212)=x112x \left( \frac{1}{4} - \frac{1}{6} \right) = x \left( \frac{3}{12} - \frac{2}{12} \right) = x \cdot \frac{1}{12}

Thus, the result of the inner integral is:

x12\frac{x}{12}

Step 2: Solve the outer integral with respect to xx

Now we compute the outer integral:

12x12dx\int_1^2 \frac{x}{12} \, dx

We can factor out the constant 112\frac{1}{12}:

11212xdx\frac{1}{12} \int_1^2 x \, dx

The antiderivative of xx is x22\frac{x^2}{2}, so:

112[x22]12=112(222122)=112(4212)\frac{1}{12} \left[ \frac{x^2}{2} \right]_1^2 = \frac{1}{12} \left( \frac{2^2}{2} - \frac{1^2}{2} \right) = \frac{1}{12} \left( \frac{4}{2} - \frac{1}{2} \right)

Simplifying the expression inside the parentheses:

112(20.5)=112×1.5=1.512=18\frac{1}{12} \left( 2 - 0.5 \right) = \frac{1}{12} \times 1.5 = \frac{1.5}{12} = \frac{1}{8}

Thus, the value of the double integral is:

0.125\boxed{0.125}

The correct answer is option (c) 0.1250.125.

Would you like further details on any step?

Here are 5 related questions for practice:

  1. How do you approach evaluating iterated integrals in general?
  2. What are the steps to finding antiderivatives of rational functions?
  3. How does changing the order of integration affect the evaluation of double integrals?
  4. What is the physical interpretation of a double integral in terms of area or volume?
  5. How can double integrals be solved using polar coordinates?

Tip: When evaluating double integrals, always check if it's possible to separate variables or simplify the expression by factoring out constants to reduce complexity.

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Math Problem Analysis

Mathematical Concepts

Calculus
Double Integrals
Iterated Integrals

Formulas

∫∫_D f(x,y) dA
Antiderivative of 1/y^2 = -1/y

Theorems

Fundamental Theorem of Calculus
Iterated Integral Property

Suitable Grade Level

Undergraduate Mathematics or Advanced High School